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Which of the following pairs will give displacement reactions?

A
NaCl solution and copper metal

B
MgCl solution and aluminium metal.

C
FeSO solution and silver metal

D
AgNO solution and copper metal

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Metal above in activity series are more reactive and can displace the less reactive metal.
 (a) solution and copper metal
is more reactive than , thus it will not give diplacement reaction.

(b) solution and aluium metal.
can not replace  because it is lower on the reactivity series.

(c) solution and silver metal
can not replace because it is lower on the reactivity series.

(d) solution and copper metal.
can be replaced by as it is above silver in the reactivity series. Therefore, this pair will give displacement reaction.

Hence, option is correct.
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Fig. 23 Work done by a force Here we assume that the force does not change during the displacement and it acts so long the body moves In eqn. (2.1), if S = 0, then W=0. Thus, If a force acts on a body and the body does not move ie, displacement is zero, then no work is done. Work is a scalar quantity. Expression for work (W = F S cos e) It is not necessary that a force always causes displacement of the body in its own direction. If under some circumstances, a force displaces the body in a direction other than the direction of force, then we determine the amount of work done by the force in either of the nwo ways: (1) by finding the component of displacement of the body in the to be more direction of force, or (2) by finding the component of force in the direction of displacement of the body. (1) if a force F s S, and S, work done to be more mt of work magnitude of de of the NO MOTION is being done mo work while shead (although ment of load is RK m body depends applied, and by the force > F.) move e distance, the is equal lacement e point of ce in the force F sition B ment of is By finding the component of displacement along the force: In Fig. 2.4, suppose a constant force F acts on a body along AB and displaces the body on an inclined surface from A to C. The displacement of the body from the point of application of force is AC = S, which is at an angle 8 to the direction of force. To find the component of displacement in the direction of force (i.e.. DISPLACEMENT S Scos - 8 Fig. 2.4 Work done by a force when the displacement is not along the force by taking the component of displacement along the force lication of two scalars F and S which are the magnitudes of force and s or vector product of two vectors F and S 20 along AB), a perpendicular CB is drawn from the point C on AB. Then the component of displacement in the direction of force is AB. Hence, work done W = F x AB But in the right angled A ABC, base AB AC TO hypotenuse AB= S cos 0 Hence. W=Fx S cos 0 (2.2) or W= Force x component of displacement in the direction of force or cos 8= (2) By finding the component of force along the displacement: In Fig. 2.5, if PA represents the magnitude and direction of force F acting on the body, then the component of force F in the direction of displacement (i.e.. along AC) is NA. DISPLACEMENT AB S Jo (iii) cosine of the angle between the directions of force F and displacement S (Le.. cos 0). Note: Since force F and displacement S are vector quantities and work W is a scalar quantity, so work is expressed as the dot product (or scalar product) of force and displacement vectors. The dot product of two vectors is a scalar. In vector form, work done W is written W = Thus, work done depends on (i) the magnitude (iii) the angle between the force and displacement. of force, (ii) the magnitude of displacement and Special cases Case (1): If the displacement is in the direction of force, i.e., 8=0°, then cos 0 = 1. W=FxS A The work done is positive. Examples: (1) In free fall of a body of mass m under gravity through a height h from A to B (Fig. 2.6), the force of gravity F (= mg) is in the direction of displacement S(= h) and the work done by the force of gravity is W = FS = mgh. MOA Ne cos Fig. 2.5 Work done by a force when the displacement is not along the force by taking the component of force along the displacement Therefore, work done W = NAX AC = NAXS But from right-angled A PNA, NA = PA cos 8 = F cos 8 Then, work done W = F cos ex S...(2.3) or Work == Component of force in the direction of displacement x displacement From eqns. (2.2) or (2.3), it is clear that the work done is equal to the product of (i) magnitude of force F, (ii) magnitude of displacement S, and Direction of motion (or displacement) E-mg h Fig. 2.6 Positive work done by the force of gravity in free fall (2) A coolie does work on the load when he raises it up against the force of gravity. Both the force exerted by the coolie (= mg) and the displacement (= h), are in upward direction. The work done by the coolie in raising the load is W = mgh. (3) When a body revolves in a circular path under the influence of a centripetal force, on completing one round, the displacement becomes zero, so the work done by the centripetal force is W = 0 (zero). 21
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Question Text
Which of the following pairs will give displacement reactions?
Updated OnApr 21, 2023
TopicMetals and Non-metals
SubjectScience
ClassClass 10
Answer TypeText solution:1 Video solution: 6
Upvotes714
Avg. Video Duration7 min