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Question 4481

A

reacts with

AgNO_{3} / NH_{4} OH

(0).

A

reacts with

Cu_{2} Cl_{2} / NH_{4} OH

$B$ does not react with $AgNO_{3} / NH_{4} OH$
$B$ reacts with $Cu_{2} Cl_{2} / NH_{4} OH$

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Question 4482

other. (Refer to Std. XI Chemistry Tembook, Chapter 14). The relationship between a chiral nolecule and its mirror image is sumilar to the relationship between left and right hem to therefore it is called handedtiess or chirality. (Origin : Greck word: Cheir means hand) The stereoisomerism in which the isomen have different spatial arrangements of groups. atoms around a chiral atom is called optical each other in terms of a measurable property called optical activity. To understand optical activity, we must know what is plane polarized light. Remember... The phenomenon of optical isomerism in organic compounds was observed first and its origin in molecular chirality was recognized later. 10.5.2 Plane polarized light: An ordinary light consists of electromagnetic waves having oscillations of electric and magnetic field in all possible planes perpendicular to direction of propagation of light. When ordinary light is passed through Nicol's prism, oscillations only in one plane emerge out. Such a light having oscillations only in one plane perpendicular to direction of propagation of light is known as plane polarized light. bo you know? Nicol prism is e special type of prism made from pieses of colcite, a eryitalline form of Cor colled polorizer 10.5.3 Optical aetivity : When an aqusous solution of certain organic compounds like sugar, lactic acid is placed in the parth of plane polarized light, the transmitted light has oscillations in a different plane than the original. In other words, the incldent light undergoes rotation of its plane of polarization. The plane of polarization rotates either to the right (clockwise) or to the feft (anticlockwise). This property of a substance by which it rotates plane of polarization of incident plane polarized light is known as optical activity. The compounds which rotate the plane of plane polarized lighr are called optically active compounds and those which do not rotote it are optically inoctive compounds. Optical ectivity of a substance is expressed numerically in terms of optical rotation. The angle through which a substance rotates the plane of plane polarized light on passing through it is called optical rotation. In occordance with the direction of eptical rotation an optically active substance is either dextrorotatory or laevorotatory. A compound which rotates the plane of plane polarized light towards right is called dextrorotatery and designated by symbol d- or by (+) sign. A compound which rotates plane of plane polarized light towards left is called laevorotatory and designoted by symbol 1 or by

(-)

sign. Isomerism in which isomeric compounds have different optical activity is known as optical isomerism. French scientist Louis Pasteur first recognized that optical octivity is associated with certain type of 3-dimensional structure of molecules. Pasteur introduced the term enantiomers for the optical isomers having equal and opposite optical rotation. 217

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Question 4483

formula pounds having same s molecular different structural formula are known as structural isomers, also known as constitutional isomers. (i) Chain 180 merism: compounds having same molecular formula but different carbon chain length are known as chain isomers.

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Question 4484

Chiral molecules are those which are:

Shows geometrical isomerism
Superimposable on their mirror images
Not superimposable on their mirror imase
Unstable molecules

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Question 4485

How Many

σ

and

π

Bond present in Benzene Diazonium chloride.

$6 σ, 3 π$
$14 σ, 4 π$
$14 σ, 6 π$
$13 σ, 4 π$

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Question 4486

51.

CH_{3} - CH_{2} - CH_{2} - CH_{3} AlCl_{3} HCl X Br_{2} hV Y

(Major)

Y

is :

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Question 4487

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Question 4488

Which of the following pair of product in given reaction can be distinguish by bicarbonate test -

CH_{3} - CH_{2} OH PCC D

A and B
B and C
C and D
B and D

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Question 4489

57. Identify the product in the following Cl[Mg]c1ccccc1 (i)

Cu_{2} Br_{2} / HBr

(ii)

Mg / dr

ether (iii)

H_{2} O

(a) c1ccccc1 (b) Br[Mg]c1ccccc1 (c) Oc1ccc(Br)cc1 (d) Oc1ccccc1

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Question 4490

57. Identify the product in the following rea Cl[Mg]c1ccccc1 (i)

Cu_{2} Br_{2} / HBr

(ii)

Mg /

dry ether (iii)

H_{2} O

(a) c1ccccc1 (b) Br[Mg]c1ccccc1 (c) Oc1ccc(Br)cc1 (d) Oc1ccccc1

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Question 4491

\#Q. Consider the following compounds/species: c1ccc2ccccc2c1c1ccoc1

9 ⊖

I A II III c1ccc2cc3ccccc3cc2c1 The number of compounds/species which obey Huckel's rule is.

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Question 4492

What volume(cc) of ethane at STP, be liberated at anode, upon electrolysis of

4.1 gm

of sodium acetate, in Kolbe's electrolysis :

$280 cc$
$560 cc$
$1120 cc$
$2240 cc$

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Question 4493

What volume(cc) of ethane at STP, be liberated at anode, upon electrolysis of

4.1 gm

of sodium acetate, in Kolbe's electrolysis : (1)

280 cc

(2)

560 cc

(3)

1120 cc

78 (4)

2240 cc

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Hydrocarbons

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Question 4494

3. What happens when ethanol is heated with conc.

HCl

and anhydrous

ZnCl_{2}

4. Mention the product formed when 2-propanol is heated with $PCl_{8}$ .
5. $CH_{3} Br + AgF_{2} \to CH_{3} F + AgBr$ . Name the reaction.
|March 2014,
6. $CH_{3} Cl + NaI - CH_{2} I + NaCl$ . Name the reaction.

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Hydrocarbons

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Question 4495

\xrightarrow{\mathrm{Br}_{2} / \mathrm{Au}} \xrightarrow{\mathrm{Alc} \mathrm{KOH}} \mathrm{X} The product '

X

' in this reaction sequence is

1) $CH_{3} - CH = CH - CH_{2} - CH_{2} - CH_{3}$
2) $CH_{3} - CH_{2} - CH = CH - CH_{2} - CH_{3}$
CC(C)=C(C)C
[C]C(C)C(C)C

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Question 4496

X

and are respectively 1)

(CH_{3})_{2} C = C (CH_{3})_{2}

and

(CH_{3})_{3}

(CH_{3})_{3} CCH = CH_{2}

and

(CH_{3})_{2} C = C (CH_{3})_{2}

(CH_{3})_{2} CH - C (CH_{3}) = CH_{2}

and 3)

(CH_{3})_{2} C = C (CH_{3})_{2}

(CH_{3})_{2} C = C (CH_{3})_{2}

and 4)

(CH_{3})_{2} CHC (CH_{3}) = CH_{2}

Topic:

Hydrocarbons

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Question 4497

Reactivity selectivity Principle which can not propagate the chain. molecule. H's. The prob

CH_{3} - CH_{2} - CH_{2} - CH_{3}

there are six equivalent

1^{\circ} H

's and four equivalent

2^{\circ}

(ii) Reactivity and more of halogen free radical: the more reactive chlorine free radical is less selective is more influenced by the probability factor. On the other hand, the less reactive

Br

radical influenced by the probability factor (Reactivity selectivity principle). in hality of alkanes (ease of abstration of '

H

' atoms): Since the rate determining step radic alonations is abstraction of hydrogen by a halogen atom be the formation of alkyl

CH_{3}

. Reactivity ratio of

H

atom for Chlorination

(1^{\circ} : 2^{\circ} : 3^{\circ} H)

Reactivity ratio of

H

atom for bromination

1 : 3.8 : 5

The above order of stability of radicals is

(1 : 82 : 1600)

corresponding alkane which in turn is due to to the ease of their formation from the to difference in the value of

Δ H

. Reactivity of any

H

-atom

\propto

number of

H

atoms of that kind

\times

reactivity of that

H

. Thus the amount of energy required to form the various classes of radicals decreases in the order

CH_{3} > 1^{\circ} > 2^{\circ} > 3^{\circ} (Δ H_{1} > Δ H_{2} > Δ H_{3} > Δ H_{4})

. Therefore, it easiest to form

3^{\circ}

radical and it is most difficult to form

CH_{3}

. We can also interpret this in an alternative way the case of abstraction of

H

atoms from hydrocarbon fallows the sequence

3^{\circ} > 2^{\circ} > 1^{\circ} CH_{4}

which should also be the case of formation of free radicals. The above order of stability is in accordance with the stability of free radicals on the basis of delocalization of odd electron. Order of stability of free radical is : Allyl, benzyl

> 3^{\circ} > 2^{\circ} > 1^{\circ} >

methyl, vinyl.

Topic:

Hydrocarbons

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Question 4498

C#CCC(C)C

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Hydrocarbons

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Question 4499

stration 20. Give number of Stereoisomers following compounds: (i) Cl/C=C/C/C=C/Cl (iii) C=CC1CCCCC1C (iv) FC=CCC=CCl (v) C=CC1CCCCC1C (vi) ClC1CCCCC1Cl (vii) CC=CC1CCCCC1C=CC (viii) C=CC1CCCCC1C=CC

d

CC=CC1CCCCC1C=CCCl/C=C/C1CCC(/C=C/Cl)CC1 (x) CC(C)=C=C=CC1CC2(CC(C)C2)C1 (xi) ClC=CC1CC2(C1)CC1(CC(C=CCl)C1)C2 (xii) ClC1C(Cl)C1Cl

(i) = 3, (ii) = 4, (iii) = 4, (iv) = 3, (v) = 4, (vi) = 8, (vii) = 10, (viii) = 6, (ix) = 3 (x) = 2, (xi) = 6, (xii) = 2

Topic:

Hydrocarbons

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Question 4500

NEET 2023 Manipur 2 MCQ (Single Correct Answer)

+ 4

- 1

(A.) (i) "

X

" \[ \mathrm{R}-\mathrm{COOH} \xrightarrow[\text { (ii) } \mathrm{H}_{2} \mathrm{O} / \mathrm{HCl}]{\text { (i) "X" }} \mathrm{R}-\mathrm{CH}_{2} \mathrm{OH} \] (ii)

H_{2} O / HCl

R - CH = CH_{2}

(i) "X" (ii)

H_{2} O, NaOH, H_{2} O_{2}

\to R - CH_{2} - CH_{2} - OH

(ii)

H_{2} O, NaOH, H_{2} O_{2}

dentify '

X

' in above reactions Correct Answ A)

B_{2} H_{6}

LiAlH_{4}

NaBH_{4}

H_{2} / Pd

Topic:

Hydrocarbons

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