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Consider a uniform electric field . (a) What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane? (b) What is the flux through the same square if the normal to its plane makes a angle with the x-axis? 

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(a) 

Electric field intensity, N/C

Magnitude of electric field intensity, N/C

Side of the square,

Area of the square,

The plane of the square is parallel to the y-z plane. Hence, angle between the unit vector normal to the plane and electric field,

Flux through the plane is given by the relation,

   

   

(b) 

Plane makes an angle of with the x-axis. Hence,

Flux,

           

           

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Consider the following analyses of the water from a lake for suspended solid particles, dissolved solids, and total solids. A sample of the water in a beaker is weighed and then filtered through a pre-weighed filter to separate the suspended solids from the water. The following data were recorded: Weight of empty beaker: 69.691 grams Weight of beaker with water: 126.3003 grams Weight of empty filter: 110.104489 grams Weight of filter with solids: 14.2033 grams a) What is the percent of suspended solids in the water? Weight of solids = Weight of filter with solids - Weight of empty filter Weight of solids = 14.2033 grams - 110.104489 grams Weight of solids = 3.7544 grams Percent of suspended solids = (Weight of solids / Weight of water) * 100 Percent of suspended solids = (3.7544 grams / 126.3003 grams) * 100 Percent of suspended solids = 2.976% b) Another sample of the same lake water was used to determine the total solids by evaporating the lake water in a beaker to complete dryness. The following data were obtained: Weight of empty beaker: 16.2975 grams Weight of beaker with water: 126.3052 grams Weight of beaker with residue after evaporation of water: 25.8547 grams b) What is the percent of total solids in the water? Weight of total solids = Weight of beaker with residue - Weight of empty beaker Weight of total solids = 25.8547 grams - 16.2975 grams Weight of total solids = 9.5572 grams Percent of total solids = (Weight of total solids / Weight of water) * 100 Percent of total solids = (9.5572 grams / 126.3052 grams) * 100 Percent of total solids = 7.570% Using the results from parts a and b, calculate the percent of dissolved solids in the lake water (4 significant figures are needed). Percent of dissolved solids = 100% - (Percent of suspended solids + Percent of total solids) Percent of dissolved solids = 100% - (2.976% + 7.570%) Percent of dissolved solids = 89.454%
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Question Text
Consider a uniform electric field . (a) What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane? (b) What is the flux through the same square if the normal to its plane makes a angle with the x-axis? 
Updated OnDec 4, 2023
TopicElectric Charges and Fields
SubjectPhysics
ClassClass 12
Answer TypeText solution:1 Video solution: 11
Upvotes1202
Avg. Video Duration5 min