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A parallel plate capacitor with air between the plates has a capacitance of 8 pF (1pF = F). What will be the capacitance if the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constant 6?
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Text solutionVerified
Let the distance between the plates initially be .
Thus initial capacitance
Substance of dielectric constant is inserted between the plates.Also, now the distance between the plates is
Thus new capacitance
Thus new capacitance
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Question Text | A parallel plate capacitor with air between the plates has a capacitance of 8 pF (1pF = F). What will be the capacitance if the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constant 6? |
Updated On | Sep 1, 2023 |
Topic | Electrostatic Potential and Capacitance |
Subject | Physics |
Class | Class 12 |
Answer Type | Text solution:1 Video solution: 2 |
Upvotes | 286 |
Avg. Video Duration | 3 min |