Class 10

Math

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Quadratic Equations

solve :$7y=−3y_{2}−4$

Consider the given equation.

$7y=−3y_{2}−4$

$3y_{2}+7y+4=0$

$3y_{2}+4y+3y+4=0$

$y(3y+4)+1(3y+4)=0$

$(y+1)(3y+4)=0$

$y=−1,3−4 $

Hence, this is the answer.

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