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Two identical copper spheres carrying charges +Q and -9 Q sepa

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Two identical copper spheres carrying charges $+ Q$ and $- 9 Q$ separated by a certain distance has attractive force $F$ . If the spheres are allowed to rouch each other and moved to distance of separation ' $x$ '. So that the force between them becomes $\frac{4 F}{9}$ . Then $X$ is equal to

Name: Video solution 1: Two identical copper spheres carrying charges +Q and −9Q separated by a certain distance has attractive force F. If the spheres are allowed to rouch each other and moved to distance of separation ' x '. So that the force between them becomes 94F. Then X is equal to
Uploaded: 2022-08-27T15:38:26.000Z
Duration: 4 min
Description: Video solution 1: Two identical copper spheres carrying charges +Q and −9Q separated by a certain distance has attractive force F. If the spheres are allowed to rouch each other and moved to distance of separation ' x '. So that the force between them becomes 94F. Then X is equal to

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Updated on: Aug 27, 2022

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Olivia Discussed

Two identical copper spheres carrying charges

+ Q

and

- 9 Q

separated by a certain distance has attractive force

F

. If the spheres are allowed to rouch each other and moved to distance of separation '

x

'. So that the force between them becomes

\frac{4 F}{9}

. Then

X

is equal to

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Question Text	Two identical copper spheres carrying charges $+ Q$ and $- 9 Q$ separated by a certain distance has attractive force $F$ . If the spheres are allowed to rouch each other and moved to distance of separation ' $x$ '. So that the force between them becomes $\frac{4 F}{9}$ . Then $X$ is equal to
Updated On	Aug 27, 2022
Topic	Electrostats
Subject	Physics
Class	Class 12
Answer Type	Video solution: 1
Upvotes	129
Avg. Video Duration	4 min

Two identical copper spheres carrying charges $+ Q$ and $- 9 Q$ separated by a certain distance has attractive force $F$ . If the spheres are allowed to rouch each other and moved to distance of separation ' $x$ '. So that the force between them becomes $\frac{4 F}{9}$ . Then $X$ is equal to

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Two identical copper spheres carrying charges +Q and −9Q separated by a certain distance has attractive force F. If the spheres are allowed to rouch each other and moved to distance of separation ' x '. So that the force between them becomes 94F​. Then X is equal to

Filo tutor solutions (1)

Practice more questions on Electrostats

Students who ask this question also asked

Two identical copper spheres carrying charges $+ Q$ and $- 9 Q$ separated by a certain distance has attractive force $F$ . If the spheres are allowed to rouch each other and moved to distance of separation ' $x$ '. So that the force between them becomes $\frac{4 F}{9}$ . Then $X$ is equal to