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Glass	23	stress to the correspon
Iron	70

called bulk modulus. It $B=-p/(\Delta V/V)$ The negative sign ind an increase in pressur occurs. That is, if $p$ is Thus for a system in Example 9.4 A square lead slab of side 50 bulk modulus $B$ is al $\mathrm{cm}$ and thickness $10\mathrm{cm}$ is subject to a bulk modulus is the shearing force (on its narrow face) of $9.0\times$ i.e., $\mathrm{Nm}{\mathrm{m}}^{-2}$ or $\mathrm{Pa}$. Tl $10^4\mathrm{N}$. The lower edge is riveted to the floor. common materials ar How much will the upper edge be displaced? The reciprocal of compressibility and i Answer The lead slab is fixed and the force is as the fractional cl applied parallel to the narrow face as shown in increase in pressure Fig. 9.7. The area of the face parallel to which $k=(1/B)=-(1/\Delta$ this force is applied is $A=50\mathrm{cm}\times 10\mathrm{cm}$ It can be seen

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Updated on: Feb 1, 2023