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A {0.1}{m} long conductor carrying a current of {50}{A} is per

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A $0.1 m$ long conductor carrying a current of $50 A$ is perpendicular to a magentic field of $1.25 m T$ . The mechanical power to move the conductor with a speed of $1 m s^{- 1}$ isa. $62.5 m W$ b. $625 m W$ c. $6.25 m W$ d. $12.5 m W$

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Oliver Discussed

0.1 m

long conductor carrying a current of

50 A

is perpendicular to a magentic field of

1.25 m T

. The mechanical power to move the conductor with a speed of

1 m s^{- 1}

isa.

62.5 m W

625 m W

6.25 m W

12.5 m W

15 mins ago

Discuss this question LIVE

15 mins ago

Text solutionVerified

Given, Length of the wire,

l = 0.1 m

Velocity of the wire,

v = 1 m s^{- 1}

Current in the wire,

I = 50 A

Magnetic field,

B = 1.25 m T = 1.25 \times 1 0^{- 3} T

The induced emf is given by,

ϵ = Bl v

Substituting the given values,

ϵ = (1.25 \times 1 0^{- 3} T) \times (0.1 m) \times (1 m s^{- 1})

ϵ = 1.25 \times 1 0^{- 4} V

The mechanical power is given by,

P = ϵ I

Substituting the given values,

P = (1.25 \times 1 0^{- 4} V) \times (50 A)

P = 6.25 \times 1 0^{- 3} W

Therefore, the mechanical power is

6.25 mW

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Question Text	A $0.1 m$ long conductor carrying a current of $50 A$ is perpendicular to a magentic field of $1.25 m T$ . The mechanical power to move the conductor with a speed of $1 m s^{- 1}$ isa. $62.5 m W$ b. $625 m W$ c. $6.25 m W$ d. $12.5 m W$
Topic	Magnetism and EMI
Subject	Physics
Class	Class 12
Answer Type	Text solution:1

A $0.1 m$ long conductor carrying a current of $50 A$ is perpendicular to a magentic field of $1.25 m T$ . The mechanical power to move the conductor with a speed of $1 m s^{- 1}$ isa. $62.5 m W$ b. $625 m W$ c. $6.25 m W$ d. $12.5 m W$

Text solutionVerified

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Text solutionVerified

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A $0.1 m$ long conductor carrying a current of $50 A$ is perpendicular to a magentic field of $1.25 m T$ . The mechanical power to move the conductor with a speed of $1 m s^{- 1}$ isa. $62.5 m W$ b. $625 m W$ c. $6.25 m W$ d. $12.5 m W$