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The reaction C(s) + CO 2 (g) ⇄ 2 CO(g) occurs at high temperat

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The reaction C(s) + CO 2 (g) ⇄ 2 CO(g) occurs at high temperatures. At 700 °C, a 200.0-L tank contains 1.0 mol of CO, 0.20 mol of CO 2 , and 0.40 mol of C at equilibrium. (a) Calculate K c for the reaction at 700 °C. (b) Calculate K c for the reaction, also at 700 °C, if the amounts at equilibrium in the 200.0-L tank are 1.0 mol of CO, 0.20 mol of CO 2 , and 0.80 mol of C. (c) Compare the results of (a) and (b). Does the quantity of carbon affect the value of K c ? Explain.

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Text solutionVerified

a) The concentration of CO is

1.0 m o l \div 200.0 L = 0.005 M

, and of CO2 is

0.20 m o l \div 200.0 L = 0.001 M

The equilibrium constant is given by:

K = [CO]^{2} / [C O_{2}]

K = (0.001 M)^{2} \div 0.005 M = 0.0002

b, c) It would be the same, the concentration of solids isn't computed in the equilibrium constant.

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The reaction C(s) + CO 2 (g) ⇄ 2 CO(g) occurs at high temperatures. At 700 °C, a 200.0-L tank contains 1.0 mol of CO, 0.20 mol of CO 2 , and 0.40 mol of C at equilibrium. (a) Calculate K c for the reaction at 700 °C. (b) Calculate K c for the reaction, also at 700 °C, if the amounts at equilibrium in the 200.0-L tank are 1.0 mol of CO, 0.20 mol of CO 2 , and 0.80 mol of C. (c) Compare the results of (a) and (b). Does the quantity of carbon affect the value of K c ? Explain.

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Question Text	The reaction C(s) + CO 2 (g) ⇄ 2 CO(g) occurs at high temperatures. At 700 °C, a 200.0-L tank contains 1.0 mol of CO, 0.20 mol of CO 2 , and 0.40 mol of C at equilibrium. (a) Calculate K c for the reaction at 700 °C. (b) Calculate K c for the reaction, also at 700 °C, if the amounts at equilibrium in the 200.0-L tank are 1.0 mol of CO, 0.20 mol of CO 2 , and 0.80 mol of C. (c) Compare the results of (a) and (b). Does the quantity of carbon affect the value of K c ? Explain.
Topic	All topics
Subject	Chemistry
Class	Class 12
Answer Type	Text solution:1

Text solutionVerified

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