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The passage of current liberates {H}_{2} at cathode and {Cl}_{

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The passage of current liberates $H_{2}$ at cathode and $Cl_{2}$ at anode. The solution is

Copper chloride in water
$NaCl$ in water
$H_{3} SO_{4}$
Water

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The passage of current liberates

H_{2}

at cathode and

Cl_{2}

at anode. The solution is

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Students who ask this question also asked

Question 1

Calculate

Δ G^{\circ}

for the reaction,

Zn_{(s)} + Cu^{2}_{(aq)} ⟶ Zn^{2} (aq) + Cu_{(s)}

Given :

E^{\circ}

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Question 2

and

Z

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y

is symmetrical. Both alkenes on hydrogenation give 2,3 -dimethylbutane. Identify

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, and 31. Discuss the nature of bonding in

[Fe (CN)]_{1}]^{4}

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Given

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33. Give reasons:- (i) Of the

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Question 3

concentration, then the units for

A

for

k

and

mol m^{3}

. the units of by using the equation:

Λ_{m} (S cm^{2} mol^{- 1}) = \frac{κ ( S cm ^{- 1} ) \times 1000 ( cm ^{3} / L )}{molarity ( mol / L )}

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1 S m m^{2} mol^{- 1} = 1 0^{4} S cm^{2} mol^{- 1} i S cm^{2} mol^{- 1} = 1 0^{- 4} s m^{2} mol^{- 1} or

Resistance of a conductivity cell filled with

0.1 mol L^{- 1} KCl

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3.4

100Ω

. If the resistance of the same cell when filled with

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KCl solution is

520Ω

, calculate the conductivity and molar conductivity of

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1.29 S / m

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\times

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/

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Question 4

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[A IEEE 2002]

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$\frac{RT}{2 F} lo g_{e} \frac{p _{1}}{p _{2}}$
$\frac{RT}{F} lo g_{e} \frac{p _{2}}{p _{1}}$
$\frac{RT}{2 F} lo g_{e} \frac{p _{2}}{p _{1}}$

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Question Text	The passage of current liberates $H_{2}$ at cathode and $Cl_{2}$ at anode. The solution is
Topic	Electrochemistry
Subject	Chemistry
Class	Class 12