On complete combustion at constant pressure, a 1.00-L sample of a gaseous mixture at $0^{\circ} C$ and $1.00$ atm (STP) evolves $75.65 kJ$ of heat. If the gas is a mixture of ethane $(C_{2} H_{6})$ and propane $(C_{3} H_{8})$ , what is the mole fraction of ethane in the mixture?

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On complete combustion at constant pressure, a 1.00-L sample of a gaseous mixture at

0^{\circ} C

and

1.00

atm (STP) evolves

75.65 kJ

of heat. If the gas is a mixture of ethane

(C_{2} H_{6})

and propane

(C_{3} H_{8})

, what is the mole fraction of ethane in the mixture?

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Question Text	On complete combustion at constant pressure, a 1.00-L sample of a gaseous mixture at $0^{\circ} C$ and $1.00$ atm (STP) evolves $75.65 kJ$ of heat. If the gas is a mixture of ethane $(C_{2} H_{6})$ and propane $(C_{3} H_{8})$ , what is the mole fraction of ethane in the mixture?
Topic	All topics
Subject	Chemistry
Class	Class 12

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