If solution $A$ had a $H^t$ concentration of $10^{-8}\mathrm{M},$ what would be its pH? If solution B had 1,000 times this H" concentration, what would be its pH? Would solution A be acidic or basic? What about solution B?

Step by Step Solution: Step 1. We can use the expression $pH=-\log [H^{+}],$ where $[H^{+}]$ is the hydrogen ion concentration in moles per liter $(M).$ Step 2. For solution A, $[H^{+}]=10^{-8}M,$ so $pH=-\log (10^{-8})=8.$ Therefore, the pH of solution A is 8. Step 3. For solution B, $[H^{+}]=1000\times 10^{-8}M=10^{-5}M,$ so $pH=-\log (10^{-5})=5.$ Therefore, the pH of solution B is 5. Step 4. Since the pH of solution A is greater than 7, it is basic. Solution B has a pH less than 7, so it is acidic.