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What is the magnitude of the gravitational force between the e

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NCERT

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Gravitational force acts on all objects in proportion to their masses. Why then, a heavy object does not fall faster than a light object?

What is the magnitude of the gravitational force between the earth and a

1 k g

object on its surface? (Mass of the earth is

6 \times 1 0^{24} k g

and radius of the earth is

6.4 \times 1 0^{6} m

The earth and the moon are attracted to each other by gravitational force. Does the earth attract the moon with a force that is greater or smaller or the same as the force with which the moon attracts the earth? Why?

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Easy

Solving time: 3 mins

What is the magnitude of the gravitational force between the earth and a $1 k g$ object on its surface? (Mass of the earth is $6 \times 1 0^{24} k g$ and radius of the earth is $6.4 \times 1 0^{6} m$ .)

Views: 6,087 students

Updated on: Feb 14, 2024

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Science (NCERT)

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Henry Discussed

What is the magnitude of the gravitational force between the earth and a

1 k g

object on its surface? (Mass of the earth is

6 \times 1 0^{24} k g

and radius of the earth is

6.4 \times 1 0^{6} m

6 mins ago

Discuss this question LIVE

6 mins ago

Text solutionVerified

Given : Mass of earth

M = 6 \times 1 0^{24} k g

Mass of object

m = 1 k g

Radius of earth

R = 6.4 \times 1 0^{6} m

Force of gravitation between them,

F = \frac{GM m}{R ^{2}}

F = \frac{6.67 \times 1 0 ^{- 11} \times ( 6 \times 1 0 ^{24} ) \times 1}{( 6.4 \times 1 0 ^{6} ) ^{2}} = 9.77 N

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Practice more questions from Science (NCERT)

Gravitational force acts on all objects in proportion to their masses. Why then, a heavy object does not fall faster than a light object?

What is the magnitude of the gravitational force between the earth and a

1 k g

object on its surface? (Mass of the earth is

6 \times 1 0^{24} k g

and radius of the earth is

6.4 \times 1 0^{6} m

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Question Text	What is the magnitude of the gravitational force between the earth and a $1 k g$ object on its surface? (Mass of the earth is $6 \times 1 0^{24} k g$ and radius of the earth is $6.4 \times 1 0^{6} m$ .)
Updated On	Feb 14, 2024
Topic	Gravitation
Subject	Science
Class	Class 9
Answer Type	Text solution:1 Video solution: 47
Upvotes	4984
Avg. Video Duration	5 min

What is the magnitude of the gravitational force between the earth and a $1 k g$ object on its surface? (Mass of the earth is $6 \times 1 0^{24} k g$ and radius of the earth is $6.4 \times 1 0^{6} m$ .)

Text solutionVerified

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