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Calculate the number of aluminum ions present in 0.051g of alu

Science

Class 9

NCERT

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Question

Hard

Solving time: 6 mins

Calculate the number of aluminum ions present in 0.051g of aluminum oxide.

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Updated on: Jun 17, 2023

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Science (NCERT)

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Calculate the number of aluminum ions present in 0.051g of aluminum oxide.

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Text solutionVerified

Molar mass of aluminium oxide

A l_{2} O_{3}

= (2 x 27) + (3 x 16)
= 54 + 48 = 102 g.

∴ 102 g of Al_{2} O_{3} contains = 2 \times 6.022 \times 1 0^{23} aluminium ions ∴ 0.051 g of Al_{2} O_{3} contains = \frac{2 \times 6.022 \times 1 0 ^{23}}{102} \times 0.051 = \frac{12.044 \times 1 0 ^{23} \times 0.051}{102} = \frac{0.614 \times 1 0 ^{23}}{102} = 0.006022 \times 1 0^{23} = 6.022 \times 1 0^{20} Al^{3 +} ions

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Practice more questions from Science (NCERT)

Calculate the number of molecules of sulphur

(S_{8})

present in

16 g

of solid sulphur.

Calculate the number of aluminum ions present in 0.051g of aluminum oxide.

(a) Calculate the relative molecular mass of water

(H_{2} O)

. (b) Calculate the molecular mass of

HNO_{3}

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Question Text	Calculate the number of aluminum ions present in 0.051g of aluminum oxide.
Updated On	Jun 17, 2023
Topic	Atoms and Molecules
Subject	Science
Class	Class 9
Answer Type	Text solution:1 Video solution: 15
Upvotes	1649
Avg. Video Duration	6 min

Calculate the number of aluminum ions present in 0.051g of aluminum oxide.

Text solutionVerified

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