Arrange the order of power dissipated in the given circuits, if the same current enters at point A in all the circuits and resistance of each resistor is R.

            Net resistance, RAB=R3             Power dissipated.             PAB=l2RABl2R3             (ii)                         Net resistance, RAB=3R             Power dissipated.             PAB=l2RAB=l2(3R)=3l2R             (iii)                         Net resistance, RAB=R2+R=32R             Power dissipated.             PAB=l2RAB=l2(32R)=32l2R             (iv)                          Net resistance 1RAB=12R+1R=32R             or RAB=23R             Power dissipated.             PAB=l2RAB=l2(23R)=23l2R Thus, (ii) > (iii) > (iv) > (i)