An object is dropped from a certain height ' h '. When it reaches to 2h, the acceleration due to gravity ' g ' becomes zero. Write the steps in a sequential order to determine the total time taken by the object to cover the total distance ' h '.(i) Determine the final velocity ' v ' at 2h level by using the formula v2−u2 =2a. Here, u=0;a=+g;s=2h.(ii) Find the values of h,g,u,2h and acceleration of the body after crossing 2h level from the given information.(iii) Now, the rest of the distance (2h) it covers with the same maximum velocity.(iv) Use the formula, v=u+at to find the time taken (t1) by the object to cover the distance 2h.(v) Use the formula, time =velocity(v)distance(2h) to find the rest of the time (t2)(vi) The total time taken, t=t1+t2

Find the value of u,g,2h,h and acceleration of the object after crossing 2h level from the given data. Determine final velocity (v) at 2h level by using the formula v2−u2=2as. Here u=0; s=2h;a=+g. Use the formula, v=u+at to find the time taken (t1) by the object to cover the distance 2h. The object covers the rest of the distance (2h) with this maximum (final) velocity v.Velocity(v)distance(2h) to findUse the formula, time =Velocity(v)distance(2h) to the rest of the time (t2) taken by the object.The total time taken, t=t1+t2

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Numericals On Uniformly Accelerated Motion

An object is dropped from a certain height ' h '. When it reac

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An object is dropped from a certain height ' $h$ '. When it reaches to $\frac{h}{2}$ , the acceleration due to gravity ' $g$ ' becomes zero.
Write the steps in a sequential order to determine the total time taken by the object to cover the total distance ' $h$ '.
(i) Determine the final velocity ' $v$ ' at $\frac{h}{2}$ level by using the formula $v^{2} - u^{2}$ $= 2 a$ . Here, $u = 0; a = + g; s = \frac{h}{2}$ .
(ii) Find the values of $h, g, u, \frac{h}{2}$ and acceleration of the body after crossing $\frac{h}{2}$ level from the given information.
(iii) Now, the rest of the distance $(\frac{h}{2})$ it covers with the same maximum velocity.
(iv) Use the formula, $v = u + a t$ to find the time taken $(t_{1})$ by the object to cover the distance $\frac{h}{2}$ .
(v) Use the formula, time $= \frac{d i s t an ce ( \frac{h}{2} )}{v e l oc i t y ( v )}$ to find the rest of the time $(t_{2})$
(vi) The total time taken, $t = t_{1} + t_{2}$

ii, i, i v, iii, v, v i

v i, v, i, ii, i v, iii

v i, i v, i, ii, v, iii

iii, i v, v i, v, i, ii

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Michael Discussed

An object is dropped from a certain height '

h

'. When it reaches to

\frac{h}{2}

, the acceleration due to gravity '

g

' becomes zero.
Write the steps in a sequential order to determine the total time taken by the object to cover the total distance '

h

'.
(i) Determine the final velocity '

v

' at

\frac{h}{2}

level by using the formula

v^{2} - u^{2}

= 2 a

. Here,

u = 0; a = + g; s = \frac{h}{2}

.
(ii) Find the values of

h, g, u, \frac{h}{2}

and acceleration of the body after crossing

\frac{h}{2}

level from the given information.
(iii) Now, the rest of the distance

(\frac{h}{2})

it covers with the same maximum velocity.
(iv) Use the formula,

v = u + a t

to find the time taken

(t_{1})

by the object to cover the distance

\frac{h}{2}

.
(v) Use the formula, time

= \frac{d i s t an ce ( \frac{h}{2} )}{v e l oc i t y ( v )}

to find the rest of the time

(t_{2})

(vi) The total time taken,

t = t_{1} + t_{2}

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Text solutionVerified

Find the value of

u, g, \frac{h}{2}, h

and acceleration of the object after crossing

\frac{h}{2}

level from the given data.
Determine final velocity

(v)

\frac{h}{2}

level by using the formula

v^{2} - u^{2} = 2 a s

.
Here

u = 0

;

s = \frac{h}{2}; a = + g

.
Use the formula,

v = u + a t

to find the time taken

(t_{1})

by the object to cover the distance

\frac{h}{2}

.
The object covers the rest of the distance

(\frac{h}{2})

with this maximum (final) velocity

v

\frac{d i s t an ce ( \frac{h}{2} )}{V e l oc i t y ( v )}

to find
Use the formula, time

= \frac{d i s t an ce ( \frac{h}{2} )}{V e l oc i t y ( v )}

to the rest of the time

(t_{2})

taken by the object.
The total time taken,

t = t_{1} + t_{2}

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Question Text	An object is dropped from a certain height ' $h$ '. When it reaches to $\frac{h}{2}$ , the acceleration due to gravity ' $g$ ' becomes zero. Write the steps in a sequential order to determine the total time taken by the object to cover the total distance ' $h$ '. (i) Determine the final velocity ' $v$ ' at $\frac{h}{2}$ level by using the formula $v^{2} - u^{2}$ $= 2 a$ . Here, $u = 0; a = + g; s = \frac{h}{2}$ . (ii) Find the values of $h, g, u, \frac{h}{2}$ and acceleration of the body after crossing $\frac{h}{2}$ level from the given information. (iii) Now, the rest of the distance $(\frac{h}{2})$ it covers with the same maximum velocity. (iv) Use the formula, $v = u + a t$ to find the time taken $(t_{1})$ by the object to cover the distance $\frac{h}{2}$ . (v) Use the formula, time $= \frac{d i s t an ce ( \frac{h}{2} )}{v e l oc i t y ( v )}$ to find the rest of the time $(t_{2})$ (vi) The total time taken, $t = t_{1} + t_{2}$
Topic	Motion
Subject	Science
Class	Class 9
Answer Type	Text solution:1
Upvotes	88

Text solutionVerified

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