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A pulley system with {VR}=4 is used to lift a load of 175 {kgf

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A pulley system with $VR = 4$ is used to lift a load of $175 kgf$ through a vertical height of $15 m$ . The effort required is $50 kgf$ in the downward direction.
$(g = 10 N kg^{- 1})$
Calculate:
(i) Distance moved by the effort.
(ii) Work done by the effort.
(iii) M.A. of the pulley system.
(iv) Efficiency of the pulley system.

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Text solutionVerified

(i) Velocity ratio

= d_{E} / d_{L}

4 = d_{E} /15 \Rightarrow d_{E} = 60 m

(ii)

W = 50 \times 10 \times 60 = 30000 J

(iii)

M A = \frac{175 \times 10}{50 \times 10} = 3.5

(iv)

η = \frac{M A}{V R} \times 100 = \frac{3.5}{4} \times 100 = 87.5%

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Harper Discussed

A pulley system with

VR = 4

is used to lift a load of

175 kgf

through a vertical height of

15 m

. The effort required is

50 kgf

in the downward direction.

(g = 10 N kg^{- 1})

Calculate:
(i) Distance moved by the effort.
(ii) Work done by the effort.
(iii) M.A. of the pulley system.
(iv) Efficiency of the pulley system.

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Question Text	A pulley system with $VR = 4$ is used to lift a load of $175 kgf$ through a vertical height of $15 m$ . The effort required is $50 kgf$ in the downward direction. $(g = 10 N kg^{- 1})$ Calculate: (i) Distance moved by the effort. (ii) Work done by the effort. (iii) M.A. of the pulley system. (iv) Efficiency of the pulley system.
Topic	Work and Energy
Subject	Science
Class	Class 9
Answer Type	Text solution:1
Upvotes	94

Text solutionVerified

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