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A pendulum swings backwards and forwards passing through Y, middle point of the oscillation.       \displaystyle{T}{h}{e}{t}{w}{e}{n}{t}{y}-{f}{i}{r}{s}{t}{t}{i}{m}{e}{t}{h}{e}{p}{e}{n}{d}\underline{{u}}{m}{p}{a}{s}{s}{t}{h}{r}{o}{u}{g}{h}{Y},{t}{h}{e}{s}\top{w}{a}{t}{c}{h}{i}{s}{s}\top{p}{e}{d}.{T}{h}{e}{r}{e}{a}{d}\in{g}{i}{s}{T}.{W}\hat{{i}}{s}{t}{h}{e}{t}{i}{m}{e}{p}{e}{r}{i}{o}{d}{o}{f}{t}{h}{e}{p}{e}{n}{d}\underline{{u}}{m}?

A
7740

B
7721

C
7720

D
7710

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Text SolutionText solutionverified iconVerified

The time taken to complete one oscillation is called the time period of a pendulum. Here the time period is the time taken to move from Y to B then back to A and then to Y. The reading of stopwatch = T Number of oscillations = 10 ∴ Time taken =Time periodNumber of oscillations =T10            
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Question Text
A pendulum swings backwards and forwards passing through Y, middle point of the oscillation.       \displaystyle{T}{h}{e}{t}{w}{e}{n}{t}{y}-{f}{i}{r}{s}{t}{t}{i}{m}{e}{t}{h}{e}{p}{e}{n}{d}\underline{{u}}{m}{p}{a}{s}{s}{t}{h}{r}{o}{u}{g}{h}{Y},{t}{h}{e}{s}\top{w}{a}{t}{c}{h}{i}{s}{s}\top{p}{e}{d}.{T}{h}{e}{r}{e}{a}{d}\in{g}{i}{s}{T}.{W}\hat{{i}}{s}{t}{h}{e}{t}{i}{m}{e}{p}{e}{r}{i}{o}{d}{o}{f}{t}{h}{e}{p}{e}{n}{d}\underline{{u}}{m}?
Answer TypeText solution:1
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