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A bowl with a semi spherical base is designed such that its centre of gravity is located at the centre of curvature of the spherical part. Explain giving reasons, to which state of equilibrium the bowl belongs. If the bowl is filled with water upto the centre of gravity, explain how the equilibrium state would be affected/unaffected.

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Initially, the bowl lies on its hemispherical base, hence its equilibrium is independent of displacements from this position. So the bowl was initially in neutral equilibrium.
Now the bowl has been filled up with water up to its centre of gravity. Due to this, the weight of the bowl increases and its centre of gravity shifts towards its base.
Hence, if we displace the bowl slightly, it will return to its original position. So the bowl now has stable equilibrium.
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Question 3
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Question 4
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3. In case of a connes mirror, if object in away from the mirror, how de the pain, sie and nature of image change? the distance of virtual image from the mur done 7/3 ve mirror is a part of hollow sphere o radies What will be the focal length of As the object is moved away from a convex S behind it berween pole and focus) increases Le. he image shifts from the pole towards the focus and the size of the image gradually decreases. When the object is at infinity (very far), the image is at its focus The image is always crect and virtual 4. An object is brought from a fer distance towards a concave mirrue, How do the nature, position and sire of image change? acing the point source of light at the focus of mcave minor, it is possible to obtain a bright on the screen, of size equal to that of the of the mirror. The completed ray diagram is Fig. 7.48 SOURCE Focal length CONCAVE MIRROR Radion of curvature x 160 cm - 80 cm Given: als of curvature R = 40 cm Radius of curvature R Focal length/- 2 20 cm When object is very far from the concave minot, its image is at the focus and it is real, diminished, and inverted As the object is brought towards the mino the image shifts away from the mirror and its size increases, but it remains smaller than the object When the object is at centre of curvature of the //or an object placed at a distance 20 cm from a mirror, the image is also at the centre of curvature and it is of size equal to the size of the object. By further bringing the object towards the mirror, the image gets magnified and it moves away from the centre of curvature. When object is at focus of nitroc the image is at infinity. The image remains real and inverted. 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Linear magnification 20 cm The image of an object placed at a distance of 30 cm on the principal axis of a concave mirror from its pale, is formed on the object itself. Find (a) the focal length and (b) linear magnification of mirror. Since the image of an object placed at the centre of curvature of a concave mirror is formed at the centre of curvature, hence according to the question, radius of curvature of mirror R = 30 cm. (a) Focal length = x Radius of curvature = x 30 cm = 15 cm Nowa 30 cm (negative), v= 30 cm (negative) Given (A) From relation 1 of f-24 cm (negative) 45 cm (negative) 811-48 -2+1 - T 48 48 cm Alternative: The object is at the centre of curvature of concave mirror, so image will form on itself Le.. at distance 48 cm in front of mirror. (b) The image is at a distance 48 cm in front of mirror. The image is inverted, real and of same size as object if Ane An object is placed at a distance of 15 cm in front of a convex mirror of radius of curvature 10 cm. (a) Where will the image form ? (b) Find the magnification m. (c) What will be the nature of image, real or virtual 7 R of of 1 1 P 1 640 Given: R=10 cm.f- -5 cm (positive). = 15 cm (negative), v= ? 1 1 1 -.-. 1 (a) From relation 1 3 4 *+ (-15) 1 11 V5 15 15 15 + M yw - 3-75 cm (b)Now from relation 1 1 (-40) (-10) 1 Thus the image will form at a distance 3-75 cm behind the mirror. 3-75 of -40 1-8 cm Le, the focal length of concave mirror is 8 cm. (b) Magnification m=(-15) 1 4 Thus the size of image is one-fourth the size of the object. 14. At what distance in front of a concave mirror focal length 10 cm, an object be placed so that real image of size five times that of the object obtained 1 f= 14 1 Given: - 10 cm (negative), m 5 (negative for the real image) 2.-5. But m -5m--orvm Su 1 1 1 Now from relation 7. 1 -10 or (c) The image will be virtual and erect. When an object is placed at a distance of 40 cm from a concave mirror, the size of image is one fourth that of the object. (a) Calculate the distance of image from the mirror. (b) What will be the focal length of the mirror ? Given: = 40 cm (negative), 1 1 10 of =-12 cm Thus the object should be placed at a 12 cm in front of the mirror. 15. At what distance in front of a concave focal length 10 cm, an object be placed virtual image of size five times that of is obtained? 6 5m 5 But m- or Given: f= 10 cm (negative), m=5 (positive for the virtual 5 Su-² of y=-5u Now from relation + 1 M V 1 1 1 1 - H (-5) 4 -1 S 10 of Ema Thus the object should be pla
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Question Text
A bowl with a semi spherical base is designed such that its centre of gravity is located at the centre of curvature of the spherical part. Explain giving reasons, to which state of equilibrium the bowl belongs. If the bowl is filled with water upto the centre of gravity, explain how the equilibrium state would be affected/unaffected.
TopicGravitation
SubjectScience
ClassClass 9
Answer TypeText solution:1
Upvotes119