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Two stereo speakers are separated by a distance of 2.4 m. A pe

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Two stereo speakers are separated by a distance of 2.4 m. A person stands at a distance of 3.2 m as shown directly in front of one of the speakers. Find the frequencies in audible range for which the listener will hear a minimum sound intensity :
Speed of the sound in air is $320 m s^{- 1}$

160 (2 n + 1)

320 (2 n + 1)

200 (2 n + 1)

100 (2 n + 1)

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Two stereo speakers are separated by a distance of 2.4 m. A person stands at a distance of 3.2 m as shown directly in front of one of the speakers. Find the frequencies in audible range for which the listener will hear a minimum sound intensity :
Speed of the sound in air is

320 m s^{- 1}

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Text solutionVerified

3. 2^{2} + 2. 4^{2} = 4 m

path difference =

0.8 m = (2 n + 1) \frac{λ}{2}

\displaystyle \lambda = \frac{1.6}{(2n+1)} \ using\ f = \frac{v}{\lambda} = \frac{320}{1.6} (2n+1).

= 200 (2 n + 1) Hz .

n = 1, 2, 3, .....49

are allowed

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Question Text	Two stereo speakers are separated by a distance of 2.4 m. A person stands at a distance of 3.2 m as shown directly in front of one of the speakers. Find the frequencies in audible range for which the listener will hear a minimum sound intensity : Speed of the sound in air is $320 m s^{- 1}$
Answer Type	Text solution:1
Upvotes	150

Two stereo speakers are separated by a distance of 2.4 m. A person stands at a distance of 3.2 m as shown directly in front of one of the speakers. Find the frequencies in audible range for which the listener will hear a minimum sound intensity :Speed of the sound in air is 320ms−1

Text solutionVerified

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Two stereo speakers are separated by a distance of 2.4 m. A person stands at a distance of 3.2 m as shown directly in front of one of the speakers. Find the frequencies in audible range for which the listener will hear a minimum sound intensity :
Speed of the sound in air is $320 m s^{- 1}$