Get 2 FREE Instant-Explanations on Filo with code FILOAPP

Two mercury droplets of radii 0.1 cm and 0.2 cm collapse into

Question

Two mercury droplets of radii $0.1 c m$ and $0.2 c m$ collapse into one single drop. What amount of energy is released/ absorbed? The surface tension of mercury $T = 435.5 \times 1 0^{- 3} N m^{- 1}$ .

32.23 \times 1 0^{- 7}

(Released)

32.23 \times 1 0^{- 7}

(Absorbed)

64.46 \times 1 0^{- 7}

(Absorbed)

64.46 \times 1 0^{- 7}

(Released)

Views: 1,023 students

Found 4 tutors discussing this question

Levi Discussed

Two mercury droplets of radii

0.1 c m

and

0.2 c m

collapse into one single drop. What amount of energy is released/ absorbed? The surface tension of mercury

T = 435.5 \times 1 0^{- 3} N m^{- 1}

15 mins ago

Discuss this question LIVE

15 mins ago

Text solutionVerified

Let

R

be the radius of big single drop formed when two small drops of radii

r_{1}

and

r_{2}

collapse together.

Then volume of bid drop

=

volume of two small drops

∴ \frac{4}{3} π R^{1} = \frac{4}{3} π r_{1}^{3} + \frac{4}{3} π r_{2}^{3}

R^{3} = r_{1}^{3} + r_{2}^{3} = (0.1)^{3} + (0.2)^{3} = 0.001 + 0.008 = 0.009 cm^{3}

∴ R = 0.21 cm

Change in surface area

= 4 π R^{2} - (4 π r_{1}^{2} + 4 π_{2}^{2})

Energy relased

= ST \times

change in surface area

= T \times [4 π R^{2} - (4 π r_{1}^{2} + 4 π r_{2}^{2})] = 4 π T [R^{2} - (r_{1}^{2} + r_{2}^{2})]

4 \times 3.142 \times 435.5 \times 1 0^{- 3} [(0.21)^{2} - {(0.1)^{2} + (0.2)^{2}}] = - 32.33 \times 1 0^{- 7} J

-

sign shows that energy is released , Hence option A is correct

Was this solution helpful?

150

Report

One destination for complete JEE/NEET preparation

One destination to cover all your homework and assignment needs

Learn Practice Revision Succeed

Instant 1:1 help, 24x7

60, 000+ Expert tutors

Textbook solutions

Big idea maths, McGraw-Hill Education etc

Essay review

Get expert feedback on your essay

Schedule classes

High dosage tutoring from Dedicated 3 experts

Trusted by 4 million+ students

Stuck on the question or explanation?

Connect with our physics tutors online and get step by step solution of this question.

231 students are taking LIVE classes

Question Text	Two mercury droplets of radii $0.1 c m$ and $0.2 c m$ collapse into one single drop. What amount of energy is released/ absorbed? The surface tension of mercury $T = 435.5 \times 1 0^{- 3} N m^{- 1}$ .
Answer Type	Text solution:1
Upvotes	150

Two mercury droplets of radii 0.1 cm and 0.2 cm collapse into one single drop. What amount of energy is released/ absorbed? The surface tension of mercury T=435.5×10−3Nm−1.

Text solutionVerified

Practice questions from similar books

Two mercury droplets of radii $0.1 c m$ and $0.2 c m$ collapse into one single drop. What amount of energy is released/ absorbed? The surface tension of mercury $T = 435.5 \times 1 0^{- 3} N m^{- 1}$ .