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The velocity of water in river is 18 km h^{-1} near the surfac

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The velocity of water in river is $18 km h^{- 1}$ near the surface. If the river is 5 m deep, then the Shearing stress between the surface layer and the bottom layer is then(coefficient of viscosity of water, $η = 1 0^{- 3} P a s$ )

1 0^{- 2} N m^{- 2}

1 0^{- 3} N m^{- 2}

1 0^{- 4} N m^{- 2}

1 0^{- 5} N m^{- 2}

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The velocity of water in river is

18 km h^{- 1}

near the surface. If the river is 5 m deep, then the Shearing stress between the surface layer and the bottom layer is then(coefficient of viscosity of water,

η = 1 0^{- 3} P a s

)

13 mins ago

Discuss this question LIVE

13 mins ago

Text solutionVerified

As the velocity of water at the bottom of the river is zero,

d v = 18 km h^{- 1} = 18 \times \frac{5}{18} = 5 m s^{- 1}

Also,

d x = 5 m

η = 1 0^{- 3} P a s

Force of viscosity,

F = η A \frac{d v}{d x}

∴

Shearing stress, =

\frac{F}{A} = η \frac{d v}{d x}

= \frac{1 0 ^{- 3} \times 5}{5} = 1 0^{- 3} N m^{- 2}

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Question Text	The velocity of water in river is $18 km h^{- 1}$ near the surface. If the river is 5 m deep, then the Shearing stress between the surface layer and the bottom layer is then(coefficient of viscosity of water, $η = 1 0^{- 3} P a s$ )
Answer Type	Text solution:1
Upvotes	150

The velocity of water in river is 18kmh−1 near the surface. If the river is 5 m deep, then the Shearing stress between the surface layer and the bottom layer is then(coefficient of viscosity of water, η=10−3Pas)

Text solutionVerified

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The velocity of water in river is $18 km h^{- 1}$ near the surface. If the river is 5 m deep, then the Shearing stress between the surface layer and the bottom layer is then(coefficient of viscosity of water, $η = 1 0^{- 3} P a s$ )