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The velocity of water in a river is 18 kmph near the surface.

Question

The velocity of water in a river is $18 km p h$ near the surface. If the river is $4 m$ deep, the shearing stress between horizontal layers of water in Nm $^{- 2}$ is $(η_{w a t er} = 1 \times 1 0^{- 3} p a . s)$ :

2.5 \times 1 0^{- 3}

12.5 \times 1 0^{- 3}

0.75 \times 1 0^{- 3}

zero

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The velocity of water in a river is

18 km p h

near the surface. If the river is

4 m

deep, the shearing stress between horizontal layers of water in Nm

^{- 2}

(η_{w a t er} = 1 \times 1 0^{- 3} p a . s)

14 mins ago

Discuss this question LIVE

14 mins ago

Text solutionVerified

Force =

η A \frac{d v}{d y}

Shearing stress

= η \frac{d v}{d y}

Now,

\frac{d v}{d y} = \frac{18 \times 1000 \times 1000}{4 m \times 3600} S^{- 1}

= 1.25 S^{- 1}

So, shearing stress =

1 0^{- 3} \times 1.25

= 1.25 \times 1 0^{- 3} P a

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Question Text	The velocity of water in a river is $18 km p h$ near the surface. If the river is $4 m$ deep, the shearing stress between horizontal layers of water in Nm $^{- 2}$ is $(η_{w a t er} = 1 \times 1 0^{- 3} p a . s)$ :
Answer Type	Text solution:1
Upvotes	150