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The value of { K }_{ c } for the reaction 3{ O }_{ 2 }( g )

Question

The value of $K_{c}$ for the reaction $3 O_{2} (g) ⇌ 2 O_{3} (g)$ is $2.0 \times 10^{- 50}$ at $25^{o} C$ . If the equilibrium concentration of $O_{2}$ in air at $25^{o} C$ is $1.6 \times 10^{- 2}$ M, what is the concentration of $O_{3}$ ?

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Sebastian Discussed

The value of

K_{c}

for the reaction

3 O_{2} (g) ⇌ 2 O_{3} (g)

2.0 \times 10^{- 50}

25^{o} C

. If the equilibrium concentration of

O_{2}

in air at

25^{o} C

1.6 \times 10^{- 2}

M, what is the concentration of

O_{3}

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7 mins ago

Text solutionVerified

The equilibrium constant expression is

K_{c} = \frac{[ O _{3} ] ^{2}}{[ O _{2} ] ^{3}}

2.0 \times 1 0^{- 50} = \frac{[ O _{3} ] ^{2}}{( 1.6 \times 1 0 ^{- 2} ) ^{3}}

[O_{3}]^{2} = 2.0 \times 1 0^{- 50} \times (1.6 \times 1 0^{- 2})^{3} = 8.192 \times 1 0^{- 56}

Hence, the equilibrium concentration of ozone is

[O_{3}] = 2.86 \times 1 0^{- 28} M

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Question Text	The value of $K_{c}$ for the reaction $3 O_{2} (g) ⇌ 2 O_{3} (g)$ is $2.0 \times 10^{- 50}$ at $25^{o} C$ . If the equilibrium concentration of $O_{2}$ in air at $25^{o} C$ is $1.6 \times 10^{- 2}$ M, what is the concentration of $O_{3}$ ?
Answer Type	Text solution:1
Upvotes	150