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The period of oscillation of a simple pendulum is . Measured value of is known to accuracy and time for 100 oscillations of the pendulum is found to be using a wrist watch of 1 s resolution. The accuracy in the determination of is

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Text SolutionText solutionverified iconVerified

Given time period
Thus, changes can be expressed as

According to the question, we can write

Again time period

and

Now,



or


Thus, accuracy in the determination of is approx .
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Question 3
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Texts: drive eq(3-3) Could you please have a look at the result given by equation (3.3) and see if you can derive it? The necessary steps to follow are indicated by the preceding sentences. The key point is to ignore quadratic (and higher) powers of the small parameter delta in (3.2). The question has been written above the photo. v=0 (2.3) where is the velocity potential. At the initial rcd, we demand that = 0 when r = b. At the free surface, the kinematic condition is given by (2.4). 50=0 (2.5) Use of the Bernoulli equation at the free kinematic condition (2.5) we find that HS+D S (2.6) The first term is evaluated at r = S and we have used the condition that the magnetic Bond number is given by 4atya (2.7) The second and third terms on the left-hand side of (2.6) represent the capillary pressure at the surface of the jet, and the fourth term on the left-hand side represents the effect of the magnetic stress. The Bernoulli constant on the right-hand side has been fixed by demanding that SI as Izco. Curiously, the Bernoulli constant is obtained by taking the alternative limit S, where = B/2 - Bs - o. At first glance, it appears then that a second equilibrium state is possible in the far field, contrary to physical intuition. To reconcile the issue, we note that under the transformation =v30.c= the problem (2.3)-(2.6) is unchanged and, consequently, solutions computed by taking S = 1 in the far field are simply transformations of those obtained by taking S = 1 in the far field. Therefore, it is expected on physical grounds that it is sufficient to consider solutions for which S = 1 as. 3. Small amplitude theory: Under a small perturbation, the jet surface is displaced to the new location S = 1 + δAe^(iθ) (3.1), where δ is a small parameter, A is a constant complex amplitude to be determined, and e^(iθ) and k are, respectively, the complex wave speed and wavenumber of the disturbance. The velocity potential is perturbed similarly, so that φ(r) = -c + M(r)e^(iθ) (3.2), where M(r) is to be found and the first term on the right-hand side corresponds to the uniform velocity of the undisturbed jet. Substituting (3.1) and (3.2) into the problem given by (2.3)-(2.6), we ultimately derive the dispersion relation (Arkhipenko & Barkov, 1980): 1 + Ka - aK - 1 + 8 (3.3) (K + (A)) where e and K are modified Bessel functions. Note that the fraction in the first bracket in (3.3) is positive for all positive A (Radwam, 1985). For A = 0, (3.3) reduces to that given by RE in the limit of O.e f doot.
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Question Text
The period of oscillation of a simple pendulum is . Measured value of is known to accuracy and time for 100 oscillations of the pendulum is found to be using a wrist watch of 1 s resolution. The accuracy in the determination of is
Updated OnSep 15, 2023
TopicOscillations
SubjectPhysics
ClassClass 11
Answer TypeText solution:1 Video solution: 8
Upvotes864
Avg. Video Duration12 min