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The mean free path of electrons in a metal is {4}{10}^{{-{8}}}

Question

The mean free path of electrons in a metal is $4 \times 10^{- 8} m$ The electric field which can give on an average $2 e V$ energy to an electron in the metal will be in the units $V / m$

8 \times 10^{7}

5 \times 10^{- 11}

8 \times 10^{- 11}

5 \times 10^{7}

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Michael Discussed

The mean free path of electrons in a metal is

4 \times 10^{- 8} m

The electric field which can give on an average

2 e V

energy to an electron in the metal will be in the units

V / m

6 mins ago

Discuss this question LIVE

6 mins ago

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Question Text	The mean free path of electrons in a metal is $4 \times 10^{- 8} m$ The electric field which can give on an average $2 e V$ energy to an electron in the metal will be in the units $V / m$
Answer Type	Text solution:1
Upvotes	150