The equivalent resistance between points A and B of the circuit given below is …………$\Omega$

Answer: BSolution: The given circuit may be redrawn as shown in the figure.
Thus, the resistance $2R,2R\text{and}Rare\in paral\le l.Hence,$1/(R_(AB)) = 1/(2R) + 1/(2R) +1/R = 2/R$Hence,$R_(AB) = R/2\displaystyle.