Question
The energy of a hydrogen atom in its ground state is −13.6 eV. The energy of the level corresponding to the quantum number n = 2 (first excited state) in the hydrogen atom is
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[d] En=−13.6n2=−13.64=−3.4eV
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Question Text | The energy of a hydrogen atom in its ground state is −13.6 eV. The energy of the level corresponding to the quantum number n = 2 (first excited state) in the hydrogen atom is |
Answer Type | Text solution:1 |
Upvotes | 150 |