The β−decay process , discoverwd around 1900 , is basically the decay of a neutron (n) in the laboratory , a proton (p) and an electron \displaystyle{\left({e}^{{{\overline}}} ight)} are observed as the decay that the kinetic energy of the electron should be a constant . But experimentally , if was observed that the electron kinectic energy has continuous spectrum Considering a three- body decay process , i.e. \displaystyle{n} ightarrow{p}+{e}^{{{\overline}}}+\overline{
u}_{{{e}}}, around 1930 , pauli expained the observed (νe) to be massaless and possessing negligible energy , and the neutrino to be at rest , momentum and energy conservation principle are applied from this calculate , the maximum kinectic energy of the electron is 0.8×106eV The kinectic energy carrect by the proton is only the recoil energy What is the maximum energy of the anti-neutrino ?

Question

The β−decay process , discoverwd around 1900 , is basically the decay of a neutron (n) in the laboratory , a proton (p) and an electron \displaystyle{\left({e}^{{{\overline}}}ight)} are observed as the decay that the kinetic energy of the electron should be a constant . But experimentally , if was observed that the electron kinectic energy has continuous spectrum Considering a three- body decay process , i.e.  \displaystyle{n}ightarrow{p}+{e}^{{{\overline}}}+\overline{
u}_{{{e}}}, around 1930 , pauli expained the observed (νe​) to be massaless and possessing negligible energy , and the neutrino to be at rest , momentum and energy conservation principle are applied from this calculate , the maximum kinectic energy of the electron is 0.8×106eV The kinectic energy carrect by the proton is only the recoil energy  What is the maximum energy of the anti-neutrino ?

Filo · Accepted Answer

Answer: CSolution: The energy sharred between anti- neutrino and electron . If the energy of electron is almost zero then the maximum energy of anti - neutrino is rearly 0.8×106eV

Question Text	The $β - d e c a y$ process , discoverwd around $1900$ , is basically the decay of a neutron $(n)$ in the laboratory , a proton $(p)$ and an electron \displaystyle{\left({e}^{{{\overline}}}\right)} are observed as the decay that the kinetic energy of the electron should be a constant . But experimentally , if was observed that the electron kinectic energy has continuous spectrum Considering a three- body decay process , i.e. \displaystyle{n}\rightarrow{p}+{e}^{{{\overline}}}+\overline{\nu}_{{{e}}}, around $1930$ , pauli expained the observed $(\overline{ν}_{e})$ to be massaless and possessing negligible energy , and the neutrino to be at rest , momentum and energy conservation principle are applied from this calculate , the maximum kinectic energy of the electron is $0.8 \times 10^{6} e V$ The kinectic energy carrect by the proton is only the recoil energy What is the maximum energy of the anti-neutrino ?
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