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Surface tension of a liquid is 5 N/m. If its thin film is made

Question

Surface tension of a liquid is 5 $N / m$ . If its thin film is made in a ring of area $0.02 m^{2}$ , then its surface energy will be :

5 \times 1 0^{- 3}

Joule

2.5 \times 1 0^{- 3}

Joule

1 \times 1 0^{- 1}

Joule

5 \times 1 0^{- 1}

Joule

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Scarlett Discussed

Surface tension of a liquid is 5

N / m

. If its thin film is made in a ring of area

0.02 m^{2}

, then its surface energy will be :

10 mins ago

Discuss this question LIVE

10 mins ago

Text solutionVerified

The surface energy in any fluid is given as the product of the surface tension of the fluid times the area on which this surface tension is acting.

Since, this is a ring with area

0.02 m^{2}

and there are 2 surfaces to it, therefore, the total area =

0.04 m^{2}

Hence, the total surface energy would be,

U = T A

U = 5 \times 0.04 = 0.2 J

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Question Text	Surface tension of a liquid is 5 $N / m$ . If its thin film is made in a ring of area $0.02 m^{2}$ , then its surface energy will be :
Answer Type	Text solution:1
Upvotes	151