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Problems in General Physics

PART SIX. ATOMIC AND NUCLEAR PHYSICS

Q.242. Find the kinetic energy of the recoil nucleus in the po

Problems in General Physics

Class 11

IE Irodov

Chapter 1: PART ONE. PHYSICAL FUNDAMENTALS OF MECHANICS

277 questions

Chapter 2: PART TWO. THERMODYNAMICS AND MOLECULAR PHYSICS

9 questions

Chapter 3: PART THREE. ELECTRODYNAMICS

46 questions

Chapter 4: PART FOUR. OSCILLATIONS AND WAVES

155 questions

Chapter 5: PART FIVE. OPTICS

215 questions

Chapter 6: PART SIX. ATOMIC AND NUCLEAR PHYSICS

271 questions

Q.241. Taking the values of atomic masses from the tables, calculate the kinetic energies of a positron and a neutrino emitted by

C^{11}

nucleus for the case when the daughter nucleus does not recoil.

Q.242. Find the kinetic energy of the recoil nucleus in the positronic decay of a Nn nucleus for the case when the energy of positrons is maximum.

Q.243. From the tables of atomic masses determine the velocity of a nucleus appearing as a result of K-capture in a Bel atom provided the daughter nucleus turns out to be in the ground state.

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Question

Hard

Solving time: 5 mins

Q.242. Find the kinetic energy of the recoil nucleus in the positronic decay of a Nn nucleus for the case when the energy of positrons is maximum.

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Problems in General Physics (IE Irodov)

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Q.242. Find the kinetic energy of the recoil nucleus in the positronic decay of a Nn nucleus for the case when the energy of positrons is maximum.

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Text solutionVerified

The K.E. of the positron is maximum when the energy of neutrino is zero. Since the recoil energy of the nucleus is quite small, it can be calculated by successive approximation.
The reaction is

N^{13} \to C^{13} + e^{+} + v_{e}

The maximum energy available to the positron (including its rest energy) is

c^{2}

(Mass of

N^{13}

nucleus - Mass of

C^{13}

nucleus)

= c^{2}

(Mass of

N^{13}

atom - Mass of

C^{13}

atom - m_e)

= 0.00239 c^{2}

- m_e

c^{2}

= (0.00239 x 931 - 0.511) MeV
= 1.71 MeV
The momentum corresponding to this energy is 1.636 MeV/c .
The recoil energy of the nucleus is then

E = \frac{p ^{2}}{2 M} = \frac{( 1.636 ) ^{2}}{2 \times 13 \times 931}

= 111 eV = 0.111 keV
on using

M c^{2} - 13 \times 931

MeV

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Question Text	Q.242. Find the kinetic energy of the recoil nucleus in the positronic decay of a Nn nucleus for the case when the energy of positrons is maximum.
Topic	Nuclei
Subject	Physics
Class	Class 12
Answer Type	Text solution:1
Upvotes	44

Q.242. Find the kinetic energy of the recoil nucleus in the positronic decay of a Nn nucleus for the case when the energy of positrons is maximum.

Text solutionVerified

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