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On bombardment of {U}^{235} by slow neutrons, 200 {MeV} energy

Question

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Solving time: 3 mins

On bombardment of $U^{235}$ by slow neutrons, $200 MeV$ energy is released. If the power output of atomic reactor is $1.6 MW$ , then the rate of fission will be

5 \times 1 0^{16}

per second

10 \times 1 0^{16}

per second

15 \times 1 0^{16}

per second

20 \times 1 0^{16}

per second

Views: 6,102 students

Updated on: Sep 6, 2023

Book:

Optics And Modern Physics (DC Pandey)

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Owen Discussed

On bombardment of

U^{235}

by slow neutrons,

200 MeV

energy is released. If the power output of atomic reactor is

1.6 MW

, then the rate of fission will be

12 mins ago

Discuss this question LIVE

12 mins ago

Text solutionVerified

Let

N

nuclei decay per second. Then,

N (200 \times 1.6 \times 1 0^{- 13}) = 1.6 \times 1 0^{6}

Solving we get

N = 5 \times 1 0^{16}

per sec

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Question Text	On bombardment of $U^{235}$ by slow neutrons, $200 MeV$ energy is released. If the power output of atomic reactor is $1.6 MW$ , then the rate of fission will be
Updated On	Sep 6, 2023
Topic	Nuclei
Subject	Physics
Class	Class 12
Answer Type	Text solution:1 Video solution: 4
Upvotes	459
Avg. Video Duration	4 min

On bombardment of $U^{235}$ by slow neutrons, $200 MeV$ energy is released. If the power output of atomic reactor is $1.6 MW$ , then the rate of fission will be

Text solutionVerified

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On bombardment of U235 by slow neutrons, 200MeV energy is released. If the power output of atomic reactor is 1.6MW, then the rate of fission will be

Text solutionVerified

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On bombardment of $U^{235}$ by slow neutrons, $200 MeV$ energy is released. If the power output of atomic reactor is $1.6 MW$ , then the rate of fission will be