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In the projectile motion shown is figure, given t_{A B}=2 {~s}

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Hard

Solving time: 4 mins

In the projectile motion shown is figure, given $t_{A B} = 2 s$ then $(g = 10 ms^{- 2})$

Name: Video solution 1: In the projectile motion shown is figure, given tAB=2 s then (g=10 ms−2)
Uploaded: 2023-09-01T09:08:52.000Z
Duration: 10 min
Description: Video solution 1: In the projectile motion shown is figure, given tAB=2 s then (g=10 ms−2)

SELECT MULTIPLE OPTION

particle is at point

B

3 s

maximum height of projectile is

20 m

initial vertical component of velocity is

20 ms^{- 1}

horizontal component of velocity is

20 ms^{- 1}

Views: 5,390 students

Updated on: Sep 1, 2023

Book:

Mechanics Volume 1 (DC Pandey)

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Harper Discussed

In the projectile motion shown is figure, given

t_{A B} = 2 s

then

(g = 10 ms^{- 2})

14 mins ago

Discuss this question LIVE

14 mins ago

Text solutionVerified

Solution(all)
Horizontal component of velocity remains unchanged

X_{O A} = 20 m = \frac{X _{A B}}{2}

∴ t_{O A} = \frac{t _{A B}}{2} = 1 s

For

A B

projectile

T = 2 s = \frac{2 u _{y}}{g}

∴ u_{y} = 10 m / s

H = \frac{u _{y}^{2}}{2 g} = \frac{( 10 ) ^{2}}{2 \times 10} = 5 m

∴

Maximum height of total projectile,

= 15 + 5 = 20 m

t_{OB} = t_{O A} + t_{A B} = 1 + 2 = 3 s

For complete projectile

T = 2 (t_{O A}) + t_{A B}

= 4 s = \frac{2 u _{y}}{g}

∴ u_{y} = 20 m / s

u_{x} = \frac{A B}{t _{A B}} = \frac{40}{2} = 20 m / s

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Question Text	In the projectile motion shown is figure, given $t_{A B} = 2 s$ then $(g = 10 ms^{- 2})$
Updated On	Sep 1, 2023
Topic	Motion in a Plane
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 1
Upvotes	206
Avg. Video Duration	10 min

In the projectile motion shown is figure, given $t_{A B} = 2 s$ then $(g = 10 ms^{- 2})$

Text solutionVerified

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