Question
Medium
Solving time: 3 mins
In a Young's double slit experiment, slits are separated by and the screen is placed away. A beam of light consisting of two wavelengths, and , is used to obtain interference fringes on the screen. The least distance from the common central maximum to the point where the bright fringes due to both the wavelengths coincide, is
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Let th fringe formed due to first wavelength and th fringe formed due to second wavelength coincide i.e. their distance from common central maxima will be same
i.e. =
Hence, distance of the point of coincidence from the central maxima is
i.e. =
Hence, distance of the point of coincidence from the central maxima is
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Question Text | In a Young's double slit experiment, slits are separated by and the screen is placed away. A beam of light consisting of two wavelengths, and , is used to obtain interference fringes on the screen. The least distance from the common central maximum to the point where the bright fringes due to both the wavelengths coincide, is |
Updated On | Apr 16, 2023 |
Topic | Wave Optics |
Subject | Physics |
Class | Class 12 |
Answer Type | Text solution:1 Video solution: 5 |
Upvotes | 462 |
Avg. Video Duration | 7 min |