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In a radioactive disintegration, the ratio of initial number o

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In a radioactive disintegration, the ratio of initial number of atoms to the number of atoms present at an instant of time equal to its mean life is

Name: Video solution 1: In a radioactive disintegration, the ratio of initial number of atoms to the number of atoms present at an instant of time equal to its mean life is
Uploaded: 2022-06-08T09:35:13.000Z
Duration: 5 min
Description: Video solution 1: In a radioactive disintegration, the ratio of initial number of atoms to the number of atoms present at an instant of time equal to its mean life is

\frac{1}{e ^{2}}

\frac{1}{e}

e

e^{2}

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Updated on: Jun 8, 2022

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Text solutionVerified

Let the initial number of atoms at time

t = 0

N_{0} .

Let

N

be the number of atoms at any instant

t

. Mean life

τ = \frac{1}{λ}

, where

λ

is disintegration constant.
Given,

t = τ

According to radioactive disintegration law,

N = N_{0} e^{- λ t}

N = N_{0} e^{- λ \times \frac{1}{λ}} = \frac{N _{0}}{e}

\frac{N _{0}}{N} = e

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Question Text	In a radioactive disintegration, the ratio of initial number of atoms to the number of atoms present at an instant of time equal to its mean life is
Updated On	Jun 8, 2022
Topic	Nuclei
Subject	Physics
Class	Class 12
Answer Type	Text solution:1 Video solution: 1
Upvotes	216
Avg. Video Duration	5 min

In a radioactive disintegration, the ratio of initial number of atoms to the number of atoms present at an instant of time equal to its mean life is

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