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If the time period (T) of vibration of a liquid drop depends o

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If the time period $(T)$ of vibration of a liquid drop depends on surface tension $(S)$ , radius $(r)$ of the drop and density $(ρ)$ of the liquid, then the expression of $T$ is

T = k ρ r^{3} / S

T = k ρ^{1/2} r^{3} / S

T = k ρ r^{3} / S^{1/2}

None of these

Views: 5,823 students

Updated on: May 8, 2023

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Mila Discussed

If the time period

(T)

of vibration of a liquid drop depends on surface tension

(S)

, radius

(r)

of the drop and density

(ρ)

of the liquid, then the expression of

T

12 mins ago

Discuss this question LIVE

12 mins ago

Text solutionVerified

Let

T \propto S^{x} r^{y} p^{z}

By substituting the dimensions of

[T] = [T]

[S] = [M T^{- 2}], [r] = [L], [ρ] = [M L^{- 3}]

and by comparing the power of both the sides

x = - 1/2, y = 3/2, z = 1/2

T \propto ρ r^{3} / S \Rightarrow T = k \frac{ρ r ^{3}}{S}

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Question Text	If the time period $(T)$ of vibration of a liquid drop depends on surface tension $(S)$ , radius $(r)$ of the drop and density $(ρ)$ of the liquid, then the expression of $T$ is
Updated On	May 8, 2023
Topic	Units and Measurements
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 3
Upvotes	362
Avg. Video Duration	6 min

If the time period $(T)$ of vibration of a liquid drop depends on surface tension $(S)$ , radius $(r)$ of the drop and density $(ρ)$ of the liquid, then the expression of $T$ is

Text solutionVerified

Filo tutor solutions (3)

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If the time period (T) of vibration of a liquid drop depends on surface tension (S), radius (r) of the drop and density (ρ) of the liquid, then the expression of T is

Text solutionVerified

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If the time period $(T)$ of vibration of a liquid drop depends on surface tension $(S)$ , radius $(r)$ of the drop and density $(ρ)$ of the liquid, then the expression of $T$ is