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Physics Part-I

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How will you 'weigh the sun', that is estimate its mass? The m

Physics Part-I

Class 11

NCERT

Chapter 1: Physical World

16 questions

Chapter 2: Units and Measurements

51 questions

Chapter 3: Motion in Straight Line

50 questions

Chapter 4: Motion in a Plane

43 questions

Chapter 5: Laws of motion

52 questions

Chapter 6: Work, Energy and Power

41 questions

Chapter 7: System of Particles and Rotational Motion

45 questions

Chapter 8: Gravitation

33 questions

A rocket is fired from the earth towards the sun. At what distance from the earths centre is the gravitational force on the rocket zero? Mass of the sun =

2 \times 1 0^{30} k g

, mass of the earth =

6 \times 1 0^{24} k g

. Neglect the effect of other planets etc. (orbital radius =

1.5 \times 1 0^{11} m

How will you 'weigh the sun', that is estimate its mass? The mean orbital radius of the earth around the sun is

1.5 \times 1 0^{8} km

A saturn year is 29.5 times the earth year. How far is the saturn from the sun if the earth is

1.50 \times 1 0^{8} km

away from the sun ?

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Question

Easy

Solving time: 2 mins

How will you 'weigh the sun', that is estimate its mass? The mean orbital radius of the earth around the sun is $1.5 \times 1 0^{8} km$ .

Name: Video solution 1: [Solved] How will you 'weigh the sun', that is estimate its mass? The mean orbital radius of the earth around the sun is 1.5× 108 km. - Physics Part-I
Uploaded: 2022-10-30T10:44:56.000Z
Duration: 7 min
Description: Video solution 1: [Solved] How will you 'weigh the sun', that is estimate its mass? The mean orbital radius of the earth around the sun is 1.5× 108 km. - Physics Part-I

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Updated on: Oct 30, 2022

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Physics Part-I (NCERT)

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How will you 'weigh the sun', that is estimate its mass? The mean orbital radius of the earth around the sun is

1.5 \times 1 0^{8} km

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Text solutionVerified

Orbital radius of the Earth around the Sun,

r = 1.5 \times 1 0^{11} m

Time taken by the Earth to complete one revolution around the Sun,

T = 1 ye a r = 365.25 d a ys

= 365.25 \times 24 \times 60 \times 60 s

Universal gravitational constant,

G = 6.67 \times 1 0^{- 11} N m^{2} k g^{- 2}

Thus, mass of the Sun :

M = \frac{4 π ^{2} r ^{3}}{G T ^{2}}

= \frac{4 \times 3.1 4 ^{2} \times ( 1.5 \times 1 0 ^{11} ) ^{3}}{6.67 \times 1 0 ^{- 11} \times ( 365.25 \times 24 \times 60 \times 60 ) ^{2}}

\approx 2 \times 1 0^{30} k g

Hence, the mass of the Sun is

2 \times 1 0^{30} k g

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Practice more questions from Physics Part-I (NCERT)

A rocket is fired from the earth towards the sun. At what distance from the earths centre is the gravitational force on the rocket zero? Mass of the sun =

2 \times 1 0^{30} k g

, mass of the earth =

6 \times 1 0^{24} k g

. Neglect the effect of other planets etc. (orbital radius =

1.5 \times 1 0^{11} m

How will you 'weigh the sun', that is estimate its mass? The mean orbital radius of the earth around the sun is

1.5 \times 1 0^{8} km

A saturn year is 29.5 times the earth year. How far is the saturn from the sun if the earth is

1.50 \times 1 0^{8} km

away from the sun ?

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Question Text	How will you 'weigh the sun', that is estimate its mass? The mean orbital radius of the earth around the sun is $1.5 \times 1 0^{8} km$ .
Updated On	Oct 30, 2022
Topic	Gravitation
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 2
Upvotes	204
Avg. Video Duration	5 min

How will you 'weigh the sun', that is estimate its mass? The mean orbital radius of the earth around the sun is $1.5 \times 1 0^{8} km$ .

Text solutionVerified

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How will you 'weigh the sun', that is estimate its mass? The mean orbital radius of the earth around the sun is $1.5 \times 1 0^{8} km$ .