Get 2 FREE Instant-Explanations on Filo with code FILOAPP

Home

Physics Part-II

Nuclei

How long can an electric lamp of 100 W be kept glowing by fusi

Physics Part-II

Class 12

NCERT

Chapter 1: Ray Optics and Optical Instruments

41 questions

Chapter 2: Wave Optics

30 questions

Chapter 3: Dual Nature of Radiation and Matter

44 questions

Chapter 4: Atoms

23 questions

Chapter 5: Nuclei

38 questions

1000 M W

fission reactor consumes half of its fuel in

5.00 y

. How much

_{92}^{235} U

did it contain initially? Assume that the reactor operates

80%

of the time, that all the energy generated arises from the fission of

_{92}^{235} U

and that this nuclide is consumed only by the fission process.

How long can an electric lamp of 100 W be kept glowing by fusion of 2.0 kg of deuterium? Take the fusion reaction as :

_{1}^{2} H +_{1}^{2} \to_{2}^{3} He + n + 3.27 M e V

Calculate the height of the potential barrier for a head on collision of two deuterons.

View all question

Chapter 6: Semiconductor Electronics: Materials, Devices and Simple Circuits

25 questions

Question

Medium

Solving time: 4 mins

How long can an electric lamp of 100 W be kept glowing by fusion of 2.0 kg of deuterium? Take the fusion reaction as :
$_{1}^{2} H +_{1}^{2} \to_{2}^{3} He + n + 3.27 M e V$ .

Views: 6,352 students

Updated on: Sep 7, 2023

Book:

Physics Part-II (NCERT)

Found 5 tutors discussing this question

Lucas Discussed

How long can an electric lamp of 100 W be kept glowing by fusion of 2.0 kg of deuterium? Take the fusion reaction as :

_{1}^{2} H +_{1}^{2} \to_{2}^{3} He + n + 3.27 M e V

14 mins ago

Discuss this question LIVE

14 mins ago

Text solutionVerified

Number of atoms in 2 kg deuterium =

\frac{6.023 \times 1 0 ^{23} \times 2000}{2} = 6.023 \times 1 0^{26}

Energy released when 2 atoms fuse =

3.27 M e V

Thus, total energy released =

\frac{3.27}{2} \times 6.023 \times 1 0^{26} M e V

= 15.75 \times 1 0^{13} J

Energy consumed by bulb per second=

100 J

Thus, time for which the bulb glows =

\frac{15.75 \times 1 0 ^{13}}{100} s

= 15.75 \times 1 0^{11} s = 4.99 \times 1 0^{7} ye a rs

Was this solution helpful?

Report

Filo tutor solutions (21)

Learn from their 1-to-1 discussion with Filo tutors.

25 mins

Uploaded on: 9/7/2023

Ask your question, on a video call with tutor

Connect instantly with this tutor

Connect now

Taught by

Anjali Pandey

Total classes on Filo by this tutor - 6,089

Teaches : Physics, Mathematics, Algebra

Connect instantly with this tutor

Connect now

Notes from this class (2 pages)

Download

Was this solution helpful?

141

Report

4 mins

Uploaded on: 5/20/2022

Ask your question, on a video call with tutor

Connect instantly with this tutor

Connect now

Taught by

Kumar Vashishtha

Total classes on Filo by this tutor - 1,883

Teaches : Physics

Connect instantly with this tutor

Connect now

Notes from this class (1 pages)

Download

Was this solution helpful?

Report

5 mins

Uploaded on: 9/7/2023

Ask your question, on a video call with tutor

Connect instantly with this tutor

Connect now

Taught by

Drishty

Total classes on Filo by this tutor - 1,646

Teaches : Physics, Biology, Organic Chemistry

Connect instantly with this tutor

Connect now

Notes from this class (3 pages)

Download

Was this solution helpful?

121

Report

See more 1-on-1 discussions (18)

One destination for complete JEE/NEET preparation

One destination to cover all your homework and assignment needs

Learn Practice Revision Succeed

Instant 1:1 help, 24x7

60, 000+ Expert tutors

Textbook solutions

Big idea maths, McGraw-Hill Education etc

Essay review

Get expert feedback on your essay

Schedule classes

High dosage tutoring from Dedicated 3 experts

Trusted by 4 million+ students

Practice more questions from Physics Part-II (NCERT)

1000 M W

fission reactor consumes half of its fuel in

5.00 y

. How much

_{92}^{235} U

did it contain initially? Assume that the reactor operates

80%

of the time, that all the energy generated arises from the fission of

_{92}^{235} U

and that this nuclide is consumed only by the fission process.

How long can an electric lamp of 100 W be kept glowing by fusion of 2.0 kg of deuterium? Take the fusion reaction as :

_{1}^{2} H +_{1}^{2} \to_{2}^{3} He + n + 3.27 M e V

Calculate the height of the potential barrier for a head on collision of two deuterons.

View all

Stuck on the question or explanation?

Connect with our Physics tutors online and get step by step solution of this question.

231 students are taking LIVE classes

Question Text	How long can an electric lamp of 100 W be kept glowing by fusion of 2.0 kg of deuterium? Take the fusion reaction as : $_{1}^{2} H +_{1}^{2} \to_{2}^{3} He + n + 3.27 M e V$ .
Updated On	Sep 7, 2023
Topic	Nuclei
Subject	Physics
Class	Class 12
Answer Type	Text solution:1 Video solution: 21
Upvotes	2234
Avg. Video Duration	8 min

How long can an electric lamp of 100 W be kept glowing by fusion of 2.0 kg of deuterium? Take the fusion reaction as :
$_{1}^{2} H +_{1}^{2} \to_{2}^{3} He + n + 3.27 M e V$ .

Text solutionVerified

Filo tutor solutions (21)

Practice more questions from Physics Part-II (NCERT)

Practice questions from Physics Part-II (NCERT)

Practice more questions from Nuclei

Practice questions on similar concepts asked by Filo students

How long can an electric lamp of 100 W be kept glowing by fusion of 2.0 kg of deuterium? Take the fusion reaction as :12​H+12​→23​He+n+3.27MeV.

Text solutionVerified

Filo tutor solutions (21)

Practice more questions from Physics Part-II (NCERT)

Practice questions from Physics Part-II (NCERT)

Practice more questions from Nuclei

Practice questions on similar concepts asked by Filo students

Related books for questions on Nuclei

How long can an electric lamp of 100 W be kept glowing by fusion of 2.0 kg of deuterium? Take the fusion reaction as :
$_{1}^{2} H +_{1}^{2} \to_{2}^{3} He + n + 3.27 M e V$ .