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Drops of liquid of density p are floating in a liquid of densi

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Drops of liquid of density p are floating in a liquid of density $ρ_{L}$ . If the surface tension is T, the radius of the drop will be

\frac{3 T}{g ( 3 ρ - ρ _{L} )}

\frac{6 T}{g ( 2 ρ - ρ _{L} )}

\frac{3 T}{g ( 2 ρ - ρ _{L} )}

\frac{3 T}{g ( 4 ρ - 3 p _{L} )}

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Drops of liquid of density p are floating in a liquid of density

ρ_{L}

. If the surface tension is T, the radius of the drop will be

10 mins ago

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Text solutionVerified

We know that

f_{T} = T \times 2 π r .

T \times 2 π r + \frac{2}{3} π r^{3} ρ_{L} g = \frac{4}{3} π r^{3} ρ g

3 T = (2 ρ - ρ_{L}) g r^{2}

r = \frac{3 T}{g ( 2 ρ - l _{L}})

Answer:- (C)

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Question Text	Drops of liquid of density p are floating in a liquid of density $ρ_{L}$ . If the surface tension is T, the radius of the drop will be
Answer Type	Text solution:1
Upvotes	150