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Chemistry Part-I

Equilibrium

Determine the solubilities of silver chromate, barium chromate

Chemistry Part-I

Class 11

NCERT

Chapter 1: Some Basic Concepts of Chemistry

44 questions

Chapter 2: Structure of Atom

85 questions

Chapter 3: Classification of Elements and Periodicity in Properties

50 questions

Chapter 4: Chemical Bonding and Molecular Structure

44 questions

Chapter 5: States of Matter

28 questions

Chapter 6: Thermodynamics and Thermochemistry

36 questions

Chapter 7: Equilibrium

101 questions

Calculate the

p H

of the resultant mixtures:
a) 10 mL of 0.2M

C a (O H)_{2}

+ 25 mL of 0.1M

H Cl

b) 10 mL of 0.01M

H_{2} SO_{4}

+ 10 mL of 0.01M

C a (O H)_{2}

c) 10 mL of 0.1M

H_{2} SO_{4}

+ 10 mL of 0.1M

K O H

Determine the solubilities of silver chromate, barium chromate, ferric hydroxide, lead chloride and mercurous iodide at 298 K from their solubility product constants. Detere also the molarities of individual ions.
The solubility product constants are:
Silver chromate,

1.1 \times 1 0^{- 12}

Barium chromate,

1.2 \times 1 0^{- 10}

Ferric hydroxide,

1.0 \times 1 0^{- 38}

Lead dichloride,

1.6 \times 1 0^{- 5}

Mercurous iodide,

4.5 \times 1 0^{- 29}

The solubility product constant of

A g_{2} C r O_{4}

and

A g B r

1.1 \times 10^{- 12}

and

5.0 \times 10^{- 13}

respectively. Calculate the ratio of the molarities of their saturated solutions.

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Question

Hard

Solving time: 6 mins

Determine the solubilities of silver chromate, barium chromate, ferric hydroxide, lead chloride and mercurous iodide at 298 K from their solubility product constants. Detere also the molarities of individual ions.
The solubility product constants are:
Silver chromate, $1.1 \times 1 0^{- 12}$
Barium chromate, $1.2 \times 1 0^{- 10}$
Ferric hydroxide, $1.0 \times 1 0^{- 38}$
Lead dichloride, $1.6 \times 1 0^{- 5}$
Mercurous iodide, $4.5 \times 1 0^{- 29}$

Name: Video solution 1: [Solved] Determine the solubilities of silver chromate, barium chromate, ferric hydroxide, lead chloride and mercurous iodide at 298 K from their solubility product constants. Detere also the molarities of individual ions.The solubility product constants are: Silver chromate, 1.1×10−12Barium chromate, 1.2×10−10Ferric hydroxide, 1.0×10−38Lead dichloride, 1.6×10−5Mercurous iodide, 4.5×10−29 - Chemistry Part-I
Uploaded: 2022-04-29T16:58:07.000Z
Duration: 2 min

Views: 6,467 students

Updated on: Apr 29, 2022

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Chemistry Part-I (NCERT)

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Jack Discussed

1.1 \times 1 0^{- 12}

Barium chromate,

1.2 \times 1 0^{- 10}

Ferric hydroxide,

1.0 \times 1 0^{- 38}

Lead dichloride,

1.6 \times 1 0^{- 5}

Mercurous iodide,

4.5 \times 1 0^{- 29}

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Text solutionVerified

(i) Silver chromate

A g_{2} C r O_{4} ⇌ 2 A g^{+} + C r O_{4}^{2 -}

[A g^{+}] = 2 s, C r O_{4}^{2 -} = s

K_{s p} = (2 s)^{2} (s) = 4 s^{3} = 1.1 \times 1 0^{- 12}

s = 6.5 \times 1 0^{- 5}

[A g^{+}] = 2 s = 1.30 \times 1 0^{- 4} M

[C r O_{4}^{2 -}] = s = 6.5 \times 1 0^{- 5} M

(ii) Barium chromate

B a C r O_{4} ⇌ B a^{2 +} + C r O_{4}^{2 -}

[B a^{2 +}] = [C r O_{4}^{2 -}] = s

K_{s p} = s \times s = s 62 = 1.2 \times 1 0^{- 10} M

[B a^{2 +}] = [C r O_{4}^{2 -}] = s = 1.09 \times 1 0^{- 5} M

(iii) Ferric hydroxide

F e (O H)_{3} ⇌ F e^{3 +} + 3 O H^{-}

[F e^{3 +}] = s, [O H^{-}] = 3 s

K_{s p} = s (3 s)^{3} = 27 s^{4} = 1.0 \times 1 0^{- 38}

[F e^{3 +}] = s = 1.38 \times 1 0^{- 10} M

[O H^{-}] = 3 s = 4.14 \times 1 0^{- 10} M

(iv)Lead dichloride

P b C l_{2} ⇌ P b^{2 +} + 2 C l^{-}

[P b^{2 +}] = s, [C l^{-}] = 2 s

K_{s p} = s \times (2 s)^{2} = 4 s^{3} = 1.6 \times 1 0^{- 5}

[P b^{2 +}] = s = 0.0159 M

[C l^{-}] = 2 s = 0.0318 M

M

(v) Mercurous iodide

H g_{2} I_{2} ⇌ 2 H g^{+} + 2 I^{-}

[H g^{+}] = [I^{-}] = 2 s

K_{s p} = (2 s)^{2} (2 s)^{2} = 16 s^{4} = 4.5 \times 1 0^{- 29}

s = 4.09 \times 1 0^{- 8} M

[H g^{+}] = [I^{-}] = 2 s = 8.18 \times 1 0^{- 8} M

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Practice more questions from Chemistry Part-I (NCERT)

Calculate the

p H

of the resultant mixtures:
a) 10 mL of 0.2M

C a (O H)_{2}

+ 25 mL of 0.1M

H Cl

b) 10 mL of 0.01M

H_{2} SO_{4}

+ 10 mL of 0.01M

C a (O H)_{2}

c) 10 mL of 0.1M

H_{2} SO_{4}

+ 10 mL of 0.1M

K O H

1.1 \times 1 0^{- 12}

Barium chromate,

1.2 \times 1 0^{- 10}

Ferric hydroxide,

1.0 \times 1 0^{- 38}

Lead dichloride,

1.6 \times 1 0^{- 5}

Mercurous iodide,

4.5 \times 1 0^{- 29}

The solubility product constant of

A g_{2} C r O_{4}

and

A g B r

1.1 \times 10^{- 12}

and

5.0 \times 10^{- 13}

respectively. Calculate the ratio of the molarities of their saturated solutions.

View all

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Question Text	Determine the solubilities of silver chromate, barium chromate, ferric hydroxide, lead chloride and mercurous iodide at 298 K from their solubility product constants. Detere also the molarities of individual ions. The solubility product constants are: Silver chromate, $1.1 \times 1 0^{- 12}$ Barium chromate, $1.2 \times 1 0^{- 10}$ Ferric hydroxide, $1.0 \times 1 0^{- 38}$ Lead dichloride, $1.6 \times 1 0^{- 5}$ Mercurous iodide, $4.5 \times 1 0^{- 29}$
Updated On	Apr 29, 2022
Topic	Equilibrium
Subject	Chemistry
Class	Class 11
Answer Type	Text solution:1 Video solution: 1
Upvotes	169
Avg. Video Duration	2 min

Text solutionVerified

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