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Excess pressure

Derive an expression for the excess pressure inside a liquid d

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Derive an expression for the excess pressure inside a liquid drop.

Name: Video solution 1: Derive an expression for the excess pressure inside a liquid drop.
Uploaded: 2023-07-06T18:11:10.000Z
Duration: 4 min
Description: Video solution 1: Derive an expression for the excess pressure inside a liquid drop.

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Updated on: Feb 27, 2024

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Text solutionVerified

The net upward force on the top hemisphere of the liquid is just the pressure difference times the area of the equatorial circle :

F_{upward} = (P_{1}^{'} - P_{0}) π r^{2}

where

F_{upward} =

upward force on the liquid due to aircurrents;

P_{1}^{'} =

Final pressure;

P_{0} =

Initial pressure;

r =

radius of the drop, assuming it to be spherical. The surface tension force downward around circle is equal to the surface tension of the circumference, since only one surface contributed to the force : Thus,

F_{downward} = T (2 π r)

where,

T =

surface tension. This gives,

P_{1} - P_{0} = \frac{2 T}{r}

which represents the excess pressure inside the liquid drop.

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Question Text	Derive an expression for the excess pressure inside a liquid drop.
Updated On	Feb 27, 2024
Topic	Mechanical Properties of Fluids
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 3
Upvotes	374
Avg. Video Duration	3 min

Derive an expression for the excess pressure inside a liquid drop.

Text solutionVerified

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