Question
Assertion : For best contrast between maxima and minima in the interference pattern of Young?s double slit experiment, the intensity of light emerging out of the two slits should be equal. Reason : The intensity of interference pattern is proportional to square of amplitude.
Found 4 tutors discussing this question
Discuss this question LIVE
11 mins ago
Text solutionVerified
When intensity of light emerging from two slits is equal, the intensity at minima, Imin=(Ia−−√−Ib−−√)2=0, or absolute dark. It provides a better contrast.
Was this solution helpful?
150
Share
Report
One destination to cover all your homework and assignment needs
Learn Practice Revision Succeed
Instant 1:1 help, 24x7
60, 000+ Expert tutors
Textbook solutions
Big idea maths, McGraw-Hill Education etc
Essay review
Get expert feedback on your essay
Schedule classes
High dosage tutoring from Dedicated 3 experts
Practice questions from similar books
Question 1
A narrow tube is bent in the form of a circle of radius R, as shown in
the figure. Two small holes S and D are made in the tube at the
positions right angle to each other. A source placed at S generated a
wave of intensity which is equally divided into two parts :
One part travels along the longer path, while the other travels along
the shorter path. Both the part waves meet at the point D where a
detector is placed. The maximum value of to produce a minima at D is given by : Stuck on the question or explanation?
Connect with our physics tutors online and get step by step solution of this question.
231 students are taking LIVE classes
Question Text | Assertion : For best contrast between maxima and minima in the interference pattern of Young?s double slit experiment, the intensity of light emerging out of the two slits should be equal. Reason : The intensity of interference pattern is proportional to square of amplitude. |
Answer Type | Text solution:1 |
Upvotes | 150 |