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System of Particles and Rotational Motion

Centre of mass

An L-shaped object made of thin rods of uniform mass density i

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Medium

Solving time: 3 mins

An $L$ -shaped object made of thin rods of uniform mass density is suspended with a string as shown in figure. If $A B = BC$ and the angle is made by $A B$ with downward vertical is $θ$ , then

(a) $tan θ = \frac{2}{3}$
(b) $tan θ = \frac{1}{2 3}$
(c) $tan θ = \frac{1}{2}$
(d) $tan θ = \frac{1}{3}$

Views: 6,090 students

Updated on: Mar 22, 2023

Book:

Arihant Physics JEE Main Chapterwise Solutions (2019-2002) (Arihant)

Exam:

JEE Mains 2019

Found 5 tutors discussing this question

William Discussed

L

-shaped object made of thin rods of uniform mass density is suspended with a string as shown in figure. If

A B = BC

and the angle is made by

A B

with downward vertical is

θ

, then

(a)

tan θ = \frac{2}{3}

(b)

tan θ = \frac{1}{2 3}

(c)

tan θ = \frac{1}{2}

(d)

tan θ = \frac{1}{3}

8 mins ago

Discuss this question LIVE

8 mins ago

Text solutionVerified

Exp. (d)
Key ldea The centre of mass of a thin rod of uniform density lies at its centre. The given system of rods can be drawn using geometry as,

Solution Image

where,

(COM)_{1}

and

(COM)_{2}

are the centre of mass of both rods

A B

and

A C

, respectively. So, in

Δ A^{'} B B^{'}

tan θ = \frac{A ^{'} B ^{'}}{A ^{'} B} = \frac{\frac{a}{4}}{\frac{3 a}{4}} = \frac{1}{3}

tan θ = \frac{1}{3}

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Question Text	An $L$ -shaped object made of thin rods of uniform mass density is suspended with a string as shown in figure. If $A B = BC$ and the angle is made by $A B$ with downward vertical is $θ$ , then (a) $tan θ = \frac{2}{3}$ (b) $tan θ = \frac{1}{2 3}$ (c) $tan θ = \frac{1}{2}$ (d) $tan θ = \frac{1}{3}$
Updated On	Mar 22, 2023
Topic	System of Particles and Rotational Motion
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 7
Upvotes	676
Avg. Video Duration	9 min

Text solutionVerified

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