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Mechanical Properties of Solids

Modulus of Elasticity and Hooke's Law

An area of cross-section of rubber string is 2 {~cm}^{2}. Its

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An area of cross-section of rubber string is $2 cm^{2}$ . Its length is doubled when stretched with a linear force of $2 \times 1 0^{5} d y n es$ . The Young's modulus of the rubber in $d y n e / cm^{2}$ will be

4 \times 1 0^{5}

1 \times 1 0^{5}

2 \times 1 0^{5}

1 \times 1 0^{4}

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An area of cross-section of rubber string is

2 cm^{2}

. Its length is doubled when stretched with a linear force of

2 \times 1 0^{5} d y n es

. The Young's modulus of the rubber in

d y n e / cm^{2}

will be

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15 mins ago

Text solutionVerified

If length of the wire is doubled then strain

= 1

∴ Y =

Stress

= \frac{Force}{Area} = \frac{2 \times 1 0 ^{5}}{2} = 1 0^{5} \frac{d y n e}{cm ^{2}}

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Question Text	An area of cross-section of rubber string is $2 cm^{2}$ . Its length is doubled when stretched with a linear force of $2 \times 1 0^{5} d y n es$ . The Young's modulus of the rubber in $d y n e / cm^{2}$ will be
Topic	Mechanical Properties of Solids
Subject	Physics
Class	Class 11
Answer Type	Text solution:1
Upvotes	44

An area of cross-section of rubber string is $2 cm^{2}$ . Its length is doubled when stretched with a linear force of $2 \times 1 0^{5} d y n es$ . The Young's modulus of the rubber in $d y n e / cm^{2}$ will be

Text solutionVerified

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An area of cross-section of rubber string is $2 cm^{2}$ . Its length is doubled when stretched with a linear force of $2 \times 1 0^{5} d y n es$ . The Young's modulus of the rubber in $d y n e / cm^{2}$ will be