An AC voltage is given by. E=E0sinT2πt. Then the mean value of voltage calculated over any time interval of T/2 seconds.

E=E0sinT2πt Mean voltage calculated over time interval 2T is,=∫02T dt ∫02T Edt=T2∫0Tsin(T2π t)dt=π 1∫0Tsin(T2π t)d(T2π )=π 1[−cosT2π t]0T=π 1[−1+1]=0

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An AC voltage is given by. E=E_0 {2 t}{T}. Then the mean valu

Question

An AC voltage is given by. $E = E_{0} sin \frac{2 π t}{T}$ . Then the mean value of voltage calculated over any time interval of $T /2$ seconds.

Is always zero

Is never zero

(2 e_{0} / π)

always

May be zero

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Levi Discussed

An AC voltage is given by.

E = E_{0} sin \frac{2 π t}{T}

. Then the mean value of voltage calculated over any time interval of

T /2

seconds.

10 mins ago

Discuss this question LIVE

10 mins ago

E = E_{0} s in \frac{2 π t}{T}

Mean voltage calculated over time interval

\frac{T}{2}

is,

= \frac{\int _{0}^{\frac{T}{2}} E d t}{\int _{0}^{\frac{T}{2}} d t}

= \frac{2}{T} \int_{0}^{T} s in (\frac{2 π}{T} t) d t

= \frac{1}{π} \int_{0}^{T} s in (\frac{2 π}{T} t) d (\frac{2 π}{T})

= \frac{1}{π} [- cos \frac{2 π}{T} t]_{0}^{T}

= \frac{1}{π} [- 1 + 1]

= 0

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Question Text	An AC voltage is given by. $E = E_{0} sin \frac{2 π t}{T}$ . Then the mean value of voltage calculated over any time interval of $T /2$ seconds.
Answer Type	Text solution:1
Upvotes	150