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A travelling acoustic wave of frequency 500 Hz is moving along

Question

A travelling acoustic wave of frequency 500 Hz is moving along the positive x-direction with a velocity of 300 $m s^{- 1}$ . The phase difference between two points $x_{1}$ and $x_{2}$ is $6 0^{o}$ . Then the minimum separation between the two pints is

1 mm

1 c m

10 c m

1 m

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A travelling acoustic wave of frequency 500 Hz is moving along the positive x-direction with a velocity of 300

m s^{- 1}

. The phase difference between two points

x_{1}

and

x_{2}

6 0^{o}

. Then the minimum separation between the two pints is

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Text solutionVerified

Given :

ν = 500 Hz

v = 300 m / s

δ = 6 0^{o} = \frac{π}{3}

radians

Wavelength of the wave

λ = \frac{v}{ν} = \frac{300}{500} = 0.6

m

Minimum distance between two points

Δ x = \frac{δ}{2 π / λ}

∴

Δ x = \frac{π /3}{2 π /0.6} = 0.1

m = 10

c m

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Question Text	A travelling acoustic wave of frequency 500 Hz is moving along the positive x-direction with a velocity of 300 $m s^{- 1}$ . The phase difference between two points $x_{1}$ and $x_{2}$ is $6 0^{o}$ . Then the minimum separation between the two pints is
Answer Type	Text solution:1
Upvotes	150