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A proton moving withh a velocity {2.5}{10}^{{{7}}}{m}/{s} ente

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A proton moving withh a velocity $2.5 \times 10^{7} m / s$ enters a magnetic field of intensity $2.5 T$ making an angle $30^{\circ}$ with the magnetic field. The force on the proton is

3 \times 10^{- 12} N

5 \times 10^{- 12} N

6 \times 10^{- 12} N

9 \times 10^{- 12} N

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Levi Discussed

A proton moving withh a velocity

2.5 \times 10^{7} m / s

enters a magnetic field of intensity

2.5 T

making an angle

30^{\circ}

with the magnetic field. The force on the proton is

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Question Text	A proton moving withh a velocity $2.5 \times 10^{7} m / s$ enters a magnetic field of intensity $2.5 T$ making an angle $30^{\circ}$ with the magnetic field. The force on the proton is
Answer Type	Video solution: 1
Upvotes	150