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A particle moves along x-axis and its acceleration at any time

Question

A particle moves along x-axis and its acceleration at any time t is a = 2 sin ( $π t)$ , where t is in seconds and a is in m/ $s^{2}$ . The initial velocity of particle (at time t = 0) is u = 0.
Q. Then the magnitude of displacement (in meters) by the particle from time t = 0 to t = t will be :

\frac{2}{π ^{2}} sin π t - \frac{2 t}{π}

- \frac{2}{π ^{2}} sin π t + \frac{2 t}{π}

\frac{2 t}{π}

none of these

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Theodore Discussed

A particle moves along x-axis and its acceleration at any time t is a = 2 sin (

π t)

, where t is in seconds and a is in m/

s^{2}

. The initial velocity of particle (at time t = 0) is u = 0.
Q. Then the magnitude of displacement (in meters) by the particle from time t = 0 to t = t will be :

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Question Text	A particle moves along x-axis and its acceleration at any time t is a = 2 sin ( $π t)$ , where t is in seconds and a is in m/ $s^{2}$ . The initial velocity of particle (at time t = 0) is u = 0. Q. Then the magnitude of displacement (in meters) by the particle from time t = 0 to t = t will be :
Answer Type	Video solution: 1
Upvotes	152

A particle moves along x-axis and its acceleration at any time t is a = 2 sin (πt), where t is in seconds and a is in m/s2 . The initial velocity of particle (at time t = 0) is u = 0. Q. Then the magnitude of displacement (in meters) by the particle from time t = 0 to t = t will be :

Filo tutor solutions (1)

Practice questions from similar books

A particle moves along x-axis and its acceleration at any time t is a = 2 sin ( $π t)$ , where t is in seconds and a is in m/ $s^{2}$ . The initial velocity of particle (at time t = 0) is u = 0.
Q. Then the magnitude of displacement (in meters) by the particle from time t = 0 to t = t will be :