A material having an index of refraction of 1.30 is used as an anti-reflective coating on the price of glass $(n = 1.50) .$ What should the minimum thickness of this film be to minimize the reflection of 500-nm light?

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A material having an index of refraction of 1.30 is used as an anti-reflective coating on the price of glass

(n = 1.50) .

What should the minimum thickness of this film be to minimize the reflection of 500-nm light?

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Text solutionVerified

There are a total of two-phase reversals caused by reflection, one at the top and one at the bottom surface of the coating.

2 n t = (m + \frac{1}{2}) λ

t = (m + \frac{1}{2}) \frac{λ}{2 n}

The minimum thickness of the film is therefore

t = (\frac{1}{2}) \frac{( 500 nm )}{2 ( 1.30 )} = 96.2 nm

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Question Text	A material having an index of refraction of 1.30 is used as an anti-reflective coating on the price of glass $(n = 1.50) .$ What should the minimum thickness of this film be to minimize the reflection of 500-nm light?
Answer Type	Text solution:1
Upvotes	150