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A hoop of radius 2 m weighs 100 kg. It rolls along a horizontal floor so that its centre of mass has a speed of 20 cm/s. How much work has to be done to stop it?

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Text SolutionText solutionverified iconVerified

Total energy of the hoop=Translational Kinetic energy+ Rotational Kinetic energy=
For hoop,
Also
Thus total energy=
Hence the work required to stop the hoop=Its total energy=
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Question Text
A hoop of radius 2 m weighs 100 kg. It rolls along a horizontal floor so that its centre of mass has a speed of 20 cm/s. How much work has to be done to stop it?
Updated OnAug 29, 2023
TopicSystem of Particles and Rotational Motion
SubjectPhysics
ClassClass 11
Answer TypeText solution:1 Video solution: 3
Upvotes341
Avg. Video Duration10 min