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A hoop of radius 2 m weighs 100 kg. It rolls along a horizontal floor so that its centre of mass has a speed of 20 cm/s. How much work has to be done to stop it?
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Text solutionVerified
Total energy of the hoop=Translational Kinetic energy+ Rotational Kinetic energy=
For hoop,
Also
Thus total energy=
Hence the work required to stop the hoop=Its total energy=
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Question Text | A hoop of radius 2 m weighs 100 kg. It rolls along a horizontal floor so that its centre of mass has a speed of 20 cm/s. How much work has to be done to stop it? |
Updated On | Aug 29, 2023 |
Topic | System of Particles and Rotational Motion |
Subject | Physics |
Class | Class 11 |
Answer Type | Text solution:1 Video solution: 3 |
Upvotes | 341 |
Avg. Video Duration | 10 min |